f

#### Question about "sprintf" "@" "do for"

```Hello,

this works:

A1=3D1
A2=3D2
A3=3D3

i=3D1
vari=3Dsprintf("A%.f",i)
print vari,"=3D",@vari
i=3Di+1
vari=3Dsprintf("A%.f",i)
print vari,"=3D",@vari
i=3Di+1
vari=3Dsprintf("A%.f",i)
print vari,"=3D",@vari

do for [i=3D1:3]{
vari=3Dsprintf("A%.f",i)
print vari
}

But I want to have "print vari,"=3D",@vari" in the loop. But it dosen't=20
work. Why can't I use "print vari,"=3D",@vari" in the loop? Is there a=20
solution for?

J=C3=B6rg

```
 0
UTF
2/2/2016 7:49:52 PM
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```Jörg Buchholz wrote:

> Hello,
>
> this works:
>
> A1=1
> A2=2
> A3=3
>
> i=1
> vari=sprintf("A%.f",i)
> print vari,"=",@vari
> i=i+1
> vari=sprintf("A%.f",i)
> print vari,"=",@vari
> i=i+1
> vari=sprintf("A%.f",i)
> print vari,"=",@vari
>
> do for [i=1:3]{
> vari=sprintf("A%.f",i)
> print vari
> }
>
> But I want to have "print vari,"=",@vari" in the loop. But it dosen't
> work. Why can't I use "print vari,"=",@vari" in the loop?

The @ indicates macro expansion, which only happens once.
And that one time is before the loop is executed.
So whatever value @vari has at the start of loop execution, that
is the value it will have every time through.

> Is there a solution for?

You don't need macros for this

do for [i=1:3] {
vari = <whatever>
print vari, ' = ', value(vari)
}

> Jörg

```
 0
Ethan
2/3/2016 12:05:25 AM
```On 03.02.2016 01:05, Ethan A Merritt wrote:

> You don't need macros for this
>
>    do for [i=1:3] {
>      vari = <whatever>
>      print vari, ' = ', value(vari)
>    }

Thanks a lot Ethan, with the keyword "value" I also found the relevant
side in the manuel.

Jörg
```
 0
UTF
2/3/2016 6:30:05 AM

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