Hello,

this works:

A1=3D1
A2=3D2
A3=3D3

i=3D1
vari=3Dsprintf("A%.f",i)
print vari,"=3D",@vari
i=3Di+1
vari=3Dsprintf("A%.f",i)
print vari,"=3D",@vari
i=3Di+1
vari=3Dsprintf("A%.f",i)
print vari,"=3D",@vari

do for [i=3D1:3]{
vari=3Dsprintf("A%.f",i)
print vari
}

But I want to have "print vari,"=3D",@vari" in the loop. But it dosen't=20
work. Why can't I use "print vari,"=3D",@vari" in the loop? Is there a=20
solution for?

J=C3=B6rg

Jörg Buchholz wrote:

> Hello,
> 
> this works:
> 
> A1=1
> A2=2
> A3=3
> 
> i=1
> vari=sprintf("A%.f",i)
> print vari,"=",@vari
> i=i+1
> vari=sprintf("A%.f",i)
> print vari,"=",@vari
> i=i+1
> vari=sprintf("A%.f",i)
> print vari,"=",@vari
> 
> do for [i=1:3]{
> vari=sprintf("A%.f",i)
> print vari
> }
> 
> But I want to have "print vari,"=",@vari" in the loop. But it dosen't
> work. Why can't I use "print vari,"=",@vari" in the loop? 

The @ indicates macro expansion, which only happens once.
And that one time is before the loop is executed.
So whatever value @vari has at the start of loop execution, that
is the value it will have every time through.

> Is there a solution for?

You don't need macros for this

  do for [i=1:3] {
    vari = <whatever>
    print vari, ' = ', value(vari)
  }

 
> Jörg

On 03.02.2016 01:05, Ethan A Merritt wrote:

> You don't need macros for this
>
>    do for [i=1:3] {
>      vari = <whatever>
>      print vari, ' = ', value(vari)
>    }

Thanks a lot Ethan, with the keyword "value" I also found the relevant 
side in the manuel.

Jörg