No Jobs for new computer guys :-(
Hi all, I was wondering if there are other guys out there who are a year or two out= of university and still looking for software type jobs? I have a degree an= d masters in IT and still I find that companies are only hiring experienced= guys with 5+ years even though the company advertises for "graduates"!=20 Where are good countries to get jobs in? I'm in Ireland and really bad now!= :-( Cheer, K. On Tuesday, August 14, 2012 11:35:00 AM UTC-7, Kevin Doyle wrote: > Hi all, >=20 > I was wondering if there are other guys out there who are a year or two o=...

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Computing Probabilities for Day of Week, Hour of Day, and Day*Hour
Dear SAS-L I've spent weeks - and written hundreds of pages of program code - on the following problem. Still not licked. The problem is probably due to the fact that I am an amateur and don't know how to routinize repetitive code. Here's the deal. I have a big dataset - 87,000 cases - each of which concern information from victims on a burglary suffered in 2002. Since burglars tend to strike when residents are out of the house, the dataset contains "From Times" and "To Times," which represent the date and time people told police that they left their home, a...

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I found this website today from an email a co-worker sent me http://www.MAVERICKMONEYMAKERSDAILYSTORE.com I watched his videos on this site, and i am blown away that he is making more than 2 million dollars a year. has anyone in this group tried this program?. Please let me know. ...

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Re: Computing Probabilities for Day of Week, Hour of Day, and Day *Hour
Dave: Does this give the results you're looking for ( sorry, percentages rather than fractions )? Something tells me PROC SUMMARY on the 'days' and 'hours' dataset ( once the inverted totalhours and totaldays are calculated ) might be a more concise solution ( i.e. rather than the FREQ / TRANSPOSE ). Have to run, why don't you play with it? Output follows. data burg; input start datetime18. end datetime18.; n = put(_n_,1.); cards; 23jul2003:13:00:00 23jul2003:13:05:00 23jul2003:19:30:00 24jul2003:01:05:00 25jul2003:19:30:00 26jul2003:19:30:00 27jul20...

Re: Computing Probabilities for Day of Week, Hour of Day, and Day*Hour
I think Harry's on the right track. Here are some additional thoughts. Use the DHMS function to create datetime values for your start and end points. The H and M arguments will be zero and your fractional times should be multiplied by 24x60x60 to derive the S argument. Loop from the start to end datetimes in hourly increments. Include an OUTPUT statement to generate hourly observations with datetimes and the fractions. INTCK and INTNX functions may be handy. Create additional variables using functions like WEEKDAY and YEAR to set up all of the granularities of interest (day of week, ISO ...

Re: Computing Probabilities for Day of Week, Hour of Day, and Day *Hour #3
Correction: Note that day*hour stuff you're looking for will involve a similar approach, looping through the hours, but recording on which day of the week they fall. data hours ( keep = start end n hour: totalhours ) days ( keep = start end n day: totaldays ) ; set burg; array hours{0:23} ; array days{7} ; /* Initialize arrays */ do _i = lbound(hours) to hbound(hours); hours(_i) = .; end; do _i = lbound(days) to hbound(days); days(_i) = .; end; _i = end - start; totalhours = intck('hour',start,end) + 1; hours_mult = 1 / totalhours ...

Re: Computing Probabilities for Day of Week, Hour of Day, and Day *Hour #2
Simpler solution, one datastep. data burg; input start datetime18. end datetime18.; n = put(_n_,1.); cards; 23jul2003:13:00:00 23jul2003:13:05:00 23jul2003:19:30:00 24jul2003:01:05:00 25jul2003:19:30:00 26jul2003:19:30:00 27jul2003:08:00:00 30jul2003:19:10:00 run; options nocenter; title 'Source Data'; proc print data=burg; format _numeric_ datetime18.; run; data hours ( keep = start end n hour: totalhours ) days ( keep = start end n day: totaldays ) ; set burg; array hours{0:23} ; array days{7} ; /* Initialize arrays */ do _i = lbound(hours)...

Re: Computing Probabilities for Day of Week, Hour of Day, and Day*Hour #3
Dave's response to Harry and me was also addressed to SAS-L, but for some reason never made it into distribution. See my comments inline. >>> "Dave Sorensen" <Dave.Sorensen@jur.ku.dk> 01/06/04 09:57AM >>> >Dear Howard and Harry, > > >I found a great XMas gift in my email box upon returning from the >holidays. Howard's post of XMas Eve, Dec 24. > >I never really got to go though your code before XMas, Harry, and upon >finding Howard's "tested" code when I returned from the holidays, I >tried it and have found th...

Misc. computer hardware and software, cell phone and satellite equipment.
I cleaned out my hobby closet and I've got the following stuff up on EBay....details and purchase through the individual item links...or go here http://cgi6.ebay.com/ws/eBayISAPI.dll?ViewSellersOtherItems&userid=mbeck%40spamcop.net&include=0&since=-1&sort=3&rows=50 for a complete list... Most of this (except for the StarTAC cell phones) is fairly old stuff, but still usable. Please don't email me to buy directly, unless you can't buy it through EBay for whatever reason and we'll see what we can do. Computer accessories / upgrades: ATI-TV (Mod...

Re: Computing Probabilities for Day of Week, Hour of Day, and Day*Hour #2
Here's some tested code. First generate some test data: data demo; drop date n; do date = '01jan2002'd to '31dec2004'd; do n = 1 to 200*ranuni(1); FromDate = date - round(30*abs(rannor(1))/50); ToDate = date + round(30*abs(rannor(1))/50); FromTime = ranuni(1); ToTime = ranuni(1); if FromDate<ToDate or FromTime<ToTime then output; end; end; format FromDate ToDate date9.; run; The dataset size can be altered by changing the date range in the outer DO or the factor 200 in the inner DO, but ...