Can someone please tell if following code leaks memory

void someFunction()
{

char MyArray[512];

memset(MyArray,0,512);

}


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LinuxGuy wrote:
> Can someone please tell if following code leaks memory
>
> void someFunction()
> {
>
> char MyArray[512];
>
> memset(MyArray,0,512);
>
> }

No, it doesn't seem to.  An easier way to make the array 0 would be
to initialise it

    char MyArray[512] = {0};

(yes, I know, the '0' in those curly braces is not necessary, I just
find it a bit more readable).


V
-- 
Please remove capital As from my address when replying by mail



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LinuxGuy wrote:
> Can someone please tell if following code leaks memory
>
> void someFunction()
> {
> 	char MyArray[512];
> 	memset(MyArray,0,512);
> }


It shouldn't, unless you're doing something funky elsewhere.  I can't
say I like the hard-coded 512, though.  Why would this be leaky?

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LinuxGuy wrote:

> Can someone please tell if following code leaks memory
> 
> void someFunction()
> {
> 
> char MyArray[512];
> 
> memset(MyArray,0,512);
> 
> }

No it wont, why did you think it might?
Eric


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>>void someFunction()
>>{
>>char MyArray[512];
>>memset(MyArray,0,512);
>>}

This piece of code wont leak memory.
what you have done is made an automatic array fo 512 char and then set
0 into it. Once you get out of the scope, MyArray will get destroyed
automatically. Hence no leaks


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LinuxGuy wrote:
> Can someone please tell if following code leaks memory
>
> void someFunction()
> {
>
> char MyArray[512];
> 
> memset(MyArray,0,512);
> 
> }

There is no leakage of memory.


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On 10 May 2006 17:26:38 -0400, "LinuxGuy" <rahul.ruikar@gmail.com>
wrote:

>Can someone please tell if following code leaks memory
>
>void someFunction()
>{
>
>char MyArray[512];
>
>memset(MyArray,0,512);
>
>}
>

No, there is no memory leak, as the array is defined within the
function as a local variable, and will completely disappear on exit.

BTW, if you will be using an initializaed array, woldn't it be a
perfect place to use a vector?

#include <vector>

void someFunction()
{
	std::vector<char> MyArray(512,'\0');
}

Regards,

Zara

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LinuxGuy wrote:
> Can someone please tell if following code leaks memory
> 
> void someFunction()
> {
> 
> char MyArray[512];
> 
> memset(MyArray,0,512);
> 
> }

No. The memory for the array is released as soon as the
control flow leaves the function. It is allocated from the
stack, not the heap.

So long,
	Thomas

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LinuxGuy wrote:

> Can someone please tell if following code leaks memory
> 
> void someFunction()
> {
> 
> char MyArray[512];
> 
> memset(MyArray,0,512);
> 
> }

No it doesn't. MyArray has automatic storage; its memory will be 
reclaimed (popped off the stack) when it goes out of scope at the end of 
someFunction.


-- 
Gerhard Menzl

#dogma int main ()

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with "kapsch" and the top level domain part with "net".

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> Can someone please tell if following code leaks memory
> 
> void someFunction()
> {
> 
> char MyArray[512];
> 
> memset(MyArray,0,512);
> 
> }
> 

No.
What makes you think it could?

Wojtek



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>char MyArray[512];
>memset(MyArray,0,512);


As you are setting the memory of fixed length  512  array and you are
not allocating any thing, hence it will never leak.

Brijesh


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No.


LinuxGuy wrote:
> Can someone please tell if following code leaks memory
>
> void someFunction()
> {
>
> char MyArray[512];
>
> memset(MyArray,0,512);
>
> }

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LinuxGuy:

There is no leaks in your code.

PD. Sory for the last post.


LinuxGuy wrote:
> Can someone please tell if following code leaks memory
>
> void someFunction()
> {
>
> char MyArray[512];
>
> memset(MyArray,0,512);
>
> }


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"LinuxGuy" <rahul.ruikar@gmail.com> writes:

> Can someone please tell if following code leaks memory

Why do you think that it does?


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