"""""""""ADD ME""""""""""
Hi , Hope you are doing great. Please let me take this opportunity to introduce myself, Iam Karthik working with BhanInfoi Inc, a NY based company. We have consultants on our bench on various technologies, my request is to add me to your distribution list and kindly do send me the requirements. i have the below list available 1. Mainframe 2. Java 3.. Financial Analyst 4. Data Architect If there is any vendor ship agreement which has to be signed then I would like to take an opportunity to represent my company and expect your cooperation... ...

Urgent Requirement in """""""""""""NEW YORK""""""""""""""""
Hello Partners, Please find the requirement below. Please send the updated resume along with rate and contact no. REQ#1: Title : Java Developer ( Rating Project) Duration : 6 months Rate : open Location : NY strong java, WebLogic 9.2, Web Services, Oracle REQ#2: Title : Java Developer Duration : 4 months Rate : open Location : NY Strong java, SQL REQ#3: Title : VB.Net Consultant Location : NY Duration : 4 months Rate : open Primarily looking at someone who has Excel, VB.net and Oracle (good to have). Req #4: Title : Java Developer (MSA Project) Duration : 6+ months Rate : open Location : NY Note : Please send your updated resume along with contact no karthik@bhaninfo.com : No phone calls please. Thanks & Regards Karthik BhanInfo karthik@bhaninfo.com ...

why "::", not "."
Why does the method of modules use a dot, and the constants a double colon? e.g. Math::PI and Math.cos -- Posted via http://www.ruby-forum.com/. On Oct 26, 2010, at 01:48 , Oleg Igor wrote: > Why does the method of modules use a dot, and the constants a double > colon? > e.g. > Math::PI and Math.cos For the same reason why inner-classes/modules use double colon, because = they're constants and that's how you look up via constant namespace. Math::PI and ActiveRecord::Base are the same type of lookup... it is = just that Base is a module and PI is a float....

"my" and "our"
Hi, while testing a program, I erroneously declared the same variable twice within a block, the first time with "my", the second time with "our": { my $fz = 'VTX_Link'; .... ( around 200 lines of code, all in the same block) our $fz = 'VTX_Linkset'; ... } So the initial contents of the $fz declared with "my" is lost, because "our" creates a lexical alias for the global $fz, thus overwriting the previous "my" declaration. It was my error, no question. But I wonder why Perl doesn't mention this - even with "use s...

"If then; if then;" and "If then; if;"
I have a raw data set which is a hierarchical file: H 321 s. main st P Mary E 21 F P william m 23 M P Susan K 3 F H 324 S. Main St I use the folowing code to read the data to creat one observation per detail(P) record including hearder record(H): data test; infile 'C:\Documents and Settings\retain.txt'; retain Address; input type $1. @; if type='H' then input @3 Address $12.; if type='P' then input @3 Name $10. @13 Age 3. @16 Gender $1.; run; but the output is not what I want: 1 321 s. main H 2 321 s. main P Mary E 21 F 3 321 s...

about "++" and "--"
why this program snippet display "8,7,7,8,-7,-8" the program is: main() { int i=8; printf("%d\n%d\n%d\n%d\n%d\n%d\n",++i,--i,i++,i--,-i++,-i--); } > why this program snippet display "8,7,7,8,-7,-8" Ask your compiler-vendor because this result is IMHO implementation-defined. Check this out: http://www.parashift.com/c++-faq-lite/misc-technical-issues.html#faq-39.15 http://www.parashift.com/c++-faq-lite/misc-technical-issues.html#faq-39.16 Regards, Irina Marudina fxc123@gmail.com wrote: > why this program snippet display "8,7,7,8,-7,-8&q...

"/a" is not "/a" ?
Hi everybody, while testing a module today I stumbled on something that I can work around but I don't quite understand. >>> a = "a" >>> b = "a" >>> a == b True >>> a is b True >>> c = "/a" >>> d = "/a" >>> c == d True # all good so far >>> c is d False # eeeeek! Why c and d point to two different objects with an identical string content rather than the same object? Manu Emanuele D'Arrigo wrote: >>>> c = "/a" >>>&...

"out" and "in out"
Hi i found the following explaination: In Ada, "in" parameters are similar to C++ const parameters. They are effectively read-only within the scope of the called subprogram. Ada "in out" parameters have a reliable initial value (that passed in from the calling subprogram) and may be modified within the scope of the called procedure. Ada "out" parameters have no reliable initial value, but are expected to be assigned a value within the called procedure. What does "have no reliable initial value" mean when considering the "out" parameter? By c...

"or" and "and"
Hi, I'm just getting to discover ruby, but I find it very nice programming language. I just still don't understand how the "or" and "and" in ruby... I was playing with ruby and for example made a def to print Stem and Leaf plot (for those who didn't have a statistics course or slept on it, e.g. http://cnx.org/content/m10157/latest/) Here is the Beta version of it: class Array def n ; self.size ; end def stem_and_leaf(st = 1) # if st != (2 or 5 or 10) then ; st = 1 ; end k = Hash.new(0) self.each {|x| k[x.to_f] += 1 } k = k.sort{|a, b| a[0].to_f <=&g...

Does it need a ";" at the very after of "if" and "for"
write code like: int main(void) { int a=10; if(a<20) {} } Compiler ok on dev-cpp . don't we have to add a ";" after if statement? marsarden said: > write code like: > > int main(void) > { > int a=10; > if(a<20) > {} > } > > Compiler ok on dev-cpp . don't we have to add a ";" after if > statement? The syntax for 'if' is: if(expression) statement There is no semicolon after the ) but before the statement. The statement is either a normal statement (which can be empty), ending in a semicolon:- if(expr) ...

A problem about "[ ]" "( )" "="
I want to read several images saved in a director,and give them to I1,I2 ,I3....,using the following codes: filelist=dir(['c:\MATLAB701\work\...\*.jpg']); for i=1 :length(filelist) I=imread(fullfile('c:\MATLAB701\work\...',filelist(i).name)); end; but failed. Then I used I(i)=imread... ,still failed. How could I do? "John" <mailofww@126.com> wrote in message news:ef19e12.-1@webx.raydaftYaTP... >I want to read several images saved in a director,and give them to > I1,I2 ,I3....,using the following codes: > filelist=dir(['c:\MATLAB701\work\.....

"In" "Out" and "Trash"
I just bought a new computer and I re-installed Eudora Light on my new computer. But when I open Eudora, the "In", "Out" and "Trash" links are not on the left side of the screen the way they were on my old computer. How can I get these links back on the left side of the screen? Thank you. On 25 Mar 2007 09:49:22 -0700, "abx" <abfunex@yahoo.com> wrote: >I just bought a new computer and I re-installed Eudora Light on my new >computer. But when I open Eudora, the "In", "Out" and "Trash" links >are ...

Urgent JAVA Requirement in """"""NEW YORK"""""""""
Hello Partners, How are you ? Please find the requirement below. Location : NY Duration : 8 mnths Rate :Open Job description: Java/J2EE Web Service Developer =B7 (4+ years of application development experience in Java/J2EE and Web service technologies. =B7 Experience with spring & Hibernate. =B7 Experience with J2EE Application Server (preferably Web logic). =B7 Preferable Aqua logic DSP Experience =B7 Preferable Sonic ESB Composite Service experience Experience w...

puts "\\".gsub("\\", "\\\\")
Hello, I have a mini-ruby quiz. Guess what this line of code writes to the console, then try it for yourself: puts "\\".gsub("\\", "\\\\") Why is that so? Martin From: martinus [mailto:martin.ankerl@gmail.com]=20 # Hello, I have a mini-ruby quiz. Guess what this line of code writes to # the console, then try it for yourself: # puts "\\".gsub("\\", "\\\\") puts "\\".gsub("\\", "\\\\") \ #=3D> nil # Why is that so? faq. escaping the escape in sub/gsub. search the archives. maybe you want somethin...

Gary Sokolich """"""
"""""""""" http://www.manta.com/c/mmlq5dm/w-gary-sokolich W Gary Sokolich 801 Kings Road Newport Beach, CA 92663-5715 (949) 650-5379 http://www.tbpe.state.tx.us/da/da022808.htm TEXAS BOARD OF PROFESSIONAL ENGINEERS February 28, 2008 Board Meeting Disciplinary Actions W. Gary Sokolich , Newport Beach, California �V File B-29812 - It was alleged that Dr. Sokolich unlawfully offered or attempted to practice engineering in Texas (...) Dr. Sokolich chose to end the proceedings by signing a Consent Order that was accepted by ...

Question about "sprintf" "@" "do for"
Hello, this works: A1=3D1 A2=3D2 A3=3D3 i=3D1 vari=3Dsprintf("A%.f",i) print vari,"=3D",@vari i=3Di+1 vari=3Dsprintf("A%.f",i) print vari,"=3D",@vari i=3Di+1 vari=3Dsprintf("A%.f",i) print vari,"=3D",@vari do for [i=3D1:3]{ vari=3Dsprintf("A%.f",i) print vari } But I want to have "print vari,"=3D",@vari" in the loop. But it dosen't=20 work. Why can't I use "print vari,"=3D",@vari" in the loop? Is there a=20 solution for? J=C3=B6rg Jörg ...

Dijkstra's "Enumeration" = "Metrics" his "Abstraction" = "Quality"
"Enumerative reasoning is only an adequate mental tool under the severe boundary condition that we only use it very moderately. We should appreciate abstraction as our main mental technique to reduce the demands made upon enumerative reasoning." ~ EW Dijkstra This is critically decisive because Dijkstra is saying that in most *software engineering" contexts, most of the time, abstraction is key relative to "metrics", the numerical, the quantitative. It is a TOWWWEEERRRING, grand slam "home run". It is of Doug William's 3-4 perfectly pitched Super Bowl touchdowns. It is growth in insight after Dijkstra one of THE very best ran into major impasses attempting to drive development with metrics. His insight is that ABSTRACTION should "lead" the way. While there is the dialectic: metrics<=>abstraction The predominant factor to engage and lead software engineering by is "abstraction". So notation wise better: metrics<=>abstraction* And to denote analyzing or summarizing the dialectic applied in whatever context, from point 'a' to 'b': a,b{ metrics<=>abstraction* Discrete points: a,b; l,q{ metrics<=>abstraction* Have at your own meaningful fun! Elliott -- Global Plans + IID = part of an optimal approach On Wed, 4 Feb 2004 23:36:17 -0500, "Universe" <universe@tAkEcovadOuT.net> wrote: >"Enumerative reasoning is only an adequate mental tool und...

(mapcar 'quote '("1" "2" "3" "4"))
(mapcar 'quote '("1" "2" "3" "4")) returns ((quote "4") (quote "4") (quote "4") (quote "4")) Interesting and (for me) unexpected. Because (mapcar 'read '("1" "2" "3" "4")) returns (1 2 3 4) and (mapcar 'princ '("1" "2" "3" "4")) gives 1234("1" "2" "3" "4") Why isn't (mapcar 'quote '("1" "2" "3" "4")) returning ((quote "1") (quote "2") (quote "3") (quote "4")) Tom Haws www.hawsedc.com Probably has to do with the fact that 'arg and (quote arg) are equivalent, and LISP gets confused by the construct 'quote, which is about the same as (quote (quote arg)). But I don't pretend to know all of the mechanics of the error; the results are somewhat different in R14, BTW: Command: (mapcar 'quote '("1" "2" "3" "4")) ((<Subr: #22e3e40> "4") (<Subr: #22e3e40> "4") (<Subr: #22e3e40> "4") (<Subr: #22e3e40> "4")) ___ "Tom Haws" <hawstom@despammed.com> wrote in message news:77317472.0309160733.45ea9d8c@posting.google.com... > (mapcar 'quote '("1" "2" "3"...

"for" with "else"?
While trying to print a none empty list, I accidentaly put an "else" statement with a "for" instead of "if". Here is what I had: if ( len(mylist)> 0) : for x,y in mylist: print x,y else: print "Empty list" which was supposed to be: if ( len(mylist)> 0) : for x,y in mylist: print x,y else: print "Empty list" Is this to be expected? (python 2.2.2) ++++++++++++++++++++++++++++++= >>> for x in range(5): .... print x*x .... else: .... print "done" .... 0 1 4 9 16...

"A" is not equal "A"?
I was trying to convert String Array to String A through cycle and than compare the result with String B but eventhough results were the same it returned false. I'am working in BlueJ 3.1.0 Code is: public boolean Method () { String[] Example = {"a","b","c"}; String A = ""; String B = "abc" for (int i = 0; i<3 ; i++) { A = A + Example[i]; } if (A == B) { return true; } } never got true... I appreciate any suggestions how to solve this Den 08.04.2014 10:06, skrev 245dav@gmail.com:...

Re: "out" and "in out"
"no reliable initial value" means, you cannot rely on the value, but it may have a value. This depends on the parameter passing mechanism, which is _not_ related to the parameter mode (contrary to what many people think). So the parameter mode is there (nearly) solely for the information of the reader. The parameter passing mechanism for all kinds of parameters is defined in the RM. There are parameters passed by copy (in and out), by reference; for some it is explicitly left undefined. In your case, the passing mechanism is by reference, so you get what you get. But don't rely...

" | " and "~" on solaris
hi, someone know how configure the input keyboard. when i want "|" on the term i have "^\" when i want "~" i have "^^". someone can help me ? Thanks gege1234 wrote: > hi, > > someone know how configure the input keyboard. > when i want "|" on the term i have "^\" > when i want "~" i have "^^". > > someone can help me ? > > Thanks man xmodmap Hope this helps -- Axel i have try "loadkeys" and my keyboard became as before thanks ...

How to change "/" to "\"
Now, the output as below /a/b/c.txt b/c.txt x:/b/c.txt , Need to change x:\b\c.txt #!/bin/ksh # echo.ksh a=/a/b/c.txt echo $a echo ${a#/*/} y=`echo x:/${a#/*/} | tr -s '/' '\'` echo $y moon wrote: > Now, the output as below > > /a/b/c.txt > b/c.txt > x:/b/c.txt , Need to change x:\b\c.txt > > > #!/bin/ksh > # echo.ksh > a=/a/b/c.txt > echo $a > echo ${a#/*/} > y=`echo x:/${a#/*/} | tr -s '/' '\'` > echo $y > > One escape necessary: echo x:/${a#/*/} | tr -s '/' '\\' Two escapes necessar...

"==" is NOT TRUE "==", WHY?
[CODE START] x=5; y=8; if (x + y + 1E-15 == 13) a = 3 else a = 8 end [CODE END] When x + y + 1E-15, the code above returns a = 8. When x + y + 1E-16, the code above returns a = 3. Why? Kindly advise. Thanks. "onemilimeter Chen" <onemm@example.com> wrote in message <g7adrj$5tr$1@fred.mathworks.com>... > [CODE START] > x=5; > y=8; > if (x + y + 1E-15 == 13) > a = 3 > else > a = 8 > end > [CODE END] > > When x + y + 1E-15, the code above returns a = 8. > When x + y + 1E-16, the code above returns a = 3. > > Why? ...