"""""""""ADD ME""""""""""Hi ,
Hope you are doing great.
Please let me take this opportunity to introduce myself, Iam Karthik
working with BhanInfoi Inc, a NY based company. We have consultants
on our bench on various technologies, my request is to add me to your
distribution list and kindly do send me the requirements. i have the
below list available
1. Mainframe
2. Java
3.. Financial Analyst
4. Data Architect
If there is any vendor ship agreement which has to be signed then I
would like to take an opportunity to represent my company and expect
your cooperation...
...
Urgent Requirement in """""""""""""NEW YORK""""""""""""""""Hello Partners,
Please find the requirement below. Please send the updated resume
along with rate and contact no.
REQ#1:
Title : Java Developer ( Rating Project)
Duration : 6 months
Rate : open
Location : NY
strong java, WebLogic 9.2, Web Services, Oracle
REQ#2:
Title : Java Developer
Duration : 4 months
Rate : open
Location : NY
Strong java, SQL
REQ#3:
Title : VB.Net Consultant
Location : NY
Duration : 4 months
Rate : open
Primarily looking at someone who has Excel, VB.net and Oracle (good to
have).
Req #4:
Title : Java Developer (MSA Project)
Duration : 6+ months
Rate : open
Location : NY
Note : Please send your updated resume along with contact no
karthik@bhaninfo.com
: No phone calls please.
Thanks & Regards
Karthik
BhanInfo
karthik@bhaninfo.com
...
why "::", not "."Why does the method of modules use a dot, and the constants a double
colon?
e.g.
Math::PI and Math.cos
--
Posted via http://www.ruby-forum.com/.
On Oct 26, 2010, at 01:48 , Oleg Igor wrote:
> Why does the method of modules use a dot, and the constants a double
> colon?
> e.g.
> Math::PI and Math.cos
For the same reason why inner-classes/modules use double colon, because =
they're constants and that's how you look up via constant namespace.
Math::PI and ActiveRecord::Base are the same type of lookup... it is =
just that Base is a module and PI is a float....
"my" and "our"Hi,
while testing a program, I erroneously declared the same variable twice
within a block, the first time with "my", the second time with "our":
{
my $fz = 'VTX_Link';
.... ( around 200 lines of code, all in the same block)
our $fz = 'VTX_Linkset';
...
}
So the initial contents of the $fz declared with "my" is lost, because
"our" creates a lexical alias for the global $fz, thus overwriting the
previous "my" declaration.
It was my error, no question. But I wonder why Perl doesn't mention
this - even with "use s...
"If then; if then;" and "If then; if;"I have a raw data set which is a hierarchical file:
H 321 s. main st
P Mary E 21 F
P william m 23 M
P Susan K 3 F
H 324 S. Main St
I use the folowing code to read the data to creat one observation per
detail(P) record including hearder record(H):
data test;
infile 'C:\Documents and Settings\retain.txt';
retain Address;
input type $1. @;
if type='H' then input @3 Address $12.;
if type='P' then input @3 Name $10. @13 Age 3. @16 Gender $1.;
run;
but the output is not what I want:
1 321 s. main H
2 321 s. main P Mary E 21 F
3 321 s...
about "++" and "--"why this program snippet display "8,7,7,8,-7,-8"
the program is:
main()
{
int i=8;
printf("%d\n%d\n%d\n%d\n%d\n%d\n",++i,--i,i++,i--,-i++,-i--);
}
> why this program snippet display "8,7,7,8,-7,-8"
Ask your compiler-vendor because this result is IMHO implementation-defined.
Check this out:
http://www.parashift.com/c++-faq-lite/misc-technical-issues.html#faq-39.15
http://www.parashift.com/c++-faq-lite/misc-technical-issues.html#faq-39.16
Regards,
Irina Marudina
fxc123@gmail.com wrote:
> why this program snippet display "8,7,7,8,-7,-8&q...
"/a" is not "/a" ?Hi everybody,
while testing a module today I stumbled on something that I can work
around but I don't quite understand.
>>> a = "a"
>>> b = "a"
>>> a == b
True
>>> a is b
True
>>> c = "/a"
>>> d = "/a"
>>> c == d
True # all good so far
>>> c is d
False # eeeeek!
Why c and d point to two different objects with an identical string
content rather than the same object?
Manu
Emanuele D'Arrigo wrote:
>>>> c = "/a"
>>>&...
"out" and "in out"Hi i found the following explaination:
In Ada, "in" parameters are similar to C++ const parameters. They are
effectively read-only within the scope of the called subprogram.
Ada "in out" parameters have a reliable initial value (that passed
in from the calling subprogram) and may be modified within the scope
of the called procedure. Ada "out" parameters have no reliable
initial value, but are expected to be assigned a value within the
called procedure.
What does "have no reliable initial value" mean when considering the "out"
parameter?
By c...
"or" and "and"Hi,
I'm just getting to discover ruby, but I find it very nice programming
language. I just still don't understand how the "or" and "and" in
ruby...
I was playing with ruby and for example made a def to print Stem and
Leaf plot (for those who didn't have a statistics course or slept on
it, e.g. http://cnx.org/content/m10157/latest/)
Here is the Beta version of it:
class Array
def n ; self.size ; end
def stem_and_leaf(st = 1)
# if st != (2 or 5 or 10) then ; st = 1 ; end
k = Hash.new(0)
self.each {|x| k[x.to_f] += 1 }
k = k.sort{|a, b| a[0].to_f <=&g...
Does it need a ";" at the very after of "if" and "for"write code like:
int main(void)
{
int a=10;
if(a<20)
{}
}
Compiler ok on dev-cpp . don't we have to add a ";" after if
statement?
marsarden said:
> write code like:
>
> int main(void)
> {
> int a=10;
> if(a<20)
> {}
> }
>
> Compiler ok on dev-cpp . don't we have to add a ";" after if
> statement?
The syntax for 'if' is:
if(expression) statement
There is no semicolon after the ) but before the statement.
The statement is either a normal statement (which can be empty), ending in a
semicolon:-
if(expr)
...
A problem about "[ ]" "( )" "="I want to read several images saved in a director,and give them to
I1,I2 ,I3....,using the following codes:
filelist=dir(['c:\MATLAB701\work\...\*.jpg']);
for i=1 :length(filelist)
I=imread(fullfile('c:\MATLAB701\work\...',filelist(i).name));
end;
but failed. Then I used I(i)=imread... ,still failed.
How could I do?
"John" <mailofww@126.com> wrote in message
news:ef19e12.-1@webx.raydaftYaTP...
>I want to read several images saved in a director,and give them to
> I1,I2 ,I3....,using the following codes:
> filelist=dir(['c:\MATLAB701\work\.....
"In" "Out" and "Trash"I just bought a new computer and I re-installed Eudora Light on my new
computer. But when I open Eudora, the "In", "Out" and "Trash" links
are not on the left side of the screen the way they were on my old
computer. How can I get these links back on the left side of the
screen? Thank you.
On 25 Mar 2007 09:49:22 -0700, "abx" <abfunex@yahoo.com> wrote:
>I just bought a new computer and I re-installed Eudora Light on my new
>computer. But when I open Eudora, the "In", "Out" and "Trash" links
>are ...
Urgent JAVA Requirement in """"""NEW YORK"""""""""Hello Partners,
How are you ? Please find the requirement below.
Location : NY
Duration : 8 mnths
Rate :Open
Job description:
Java/J2EE Web Service Developer
=B7 (4+ years of application development experience in Java/J2EE
and Web service technologies.
=B7 Experience with spring & Hibernate.
=B7 Experience with J2EE Application Server (preferably Web
logic).
=B7 Preferable Aqua logic DSP Experience
=B7 Preferable Sonic ESB Composite Service experience
Experience w...
puts "\\".gsub("\\", "\\\\")Hello, I have a mini-ruby quiz. Guess what this line of code writes to
the console, then try it for yourself:
puts "\\".gsub("\\", "\\\\")
Why is that so?
Martin
From: martinus [mailto:martin.ankerl@gmail.com]=20
# Hello, I have a mini-ruby quiz. Guess what this line of code writes to
# the console, then try it for yourself:
# puts "\\".gsub("\\", "\\\\")
puts "\\".gsub("\\", "\\\\")
\
#=3D> nil
# Why is that so?
faq. escaping the escape in sub/gsub. search the archives.
maybe you want somethin...
Gary Sokolich """"""""""""""""
http://www.manta.com/c/mmlq5dm/w-gary-sokolich
W Gary Sokolich
801 Kings Road
Newport Beach, CA 92663-5715
(949) 650-5379
http://www.tbpe.state.tx.us/da/da022808.htm
TEXAS BOARD OF PROFESSIONAL ENGINEERS
February 28, 2008 Board Meeting Disciplinary Actions
W. Gary Sokolich , Newport Beach, California �V File B-29812 - It was
alleged that Dr. Sokolich unlawfully offered or attempted to practice
engineering in Texas (...) Dr. Sokolich chose to end the proceedings by
signing a Consent Order that was accepted by ...
Question about "sprintf" "@" "do for"Hello,
this works:
A1=3D1
A2=3D2
A3=3D3
i=3D1
vari=3Dsprintf("A%.f",i)
print vari,"=3D",@vari
i=3Di+1
vari=3Dsprintf("A%.f",i)
print vari,"=3D",@vari
i=3Di+1
vari=3Dsprintf("A%.f",i)
print vari,"=3D",@vari
do for [i=3D1:3]{
vari=3Dsprintf("A%.f",i)
print vari
}
But I want to have "print vari,"=3D",@vari" in the loop. But it dosen't=20
work. Why can't I use "print vari,"=3D",@vari" in the loop? Is there a=20
solution for?
J=C3=B6rg
Jörg ...
Dijkstra's "Enumeration" = "Metrics" his "Abstraction" = "Quality""Enumerative reasoning is only an adequate mental tool under the severe
boundary condition that we only use it very moderately. We should appreciate
abstraction as our main mental technique to reduce the demands made upon
enumerative reasoning." ~ EW Dijkstra
This is critically decisive because Dijkstra is saying that in most
*software engineering" contexts, most of the time, abstraction is key
relative to "metrics", the numerical, the quantitative.
It is a TOWWWEEERRRING, grand slam "home run". It is of Doug William's 3-4
perfectly pitched Super Bowl touchdowns.
It is growth in insight after Dijkstra one of THE very best ran into major
impasses attempting to drive development with metrics. His insight is that
ABSTRACTION should "lead" the way.
While there is the dialectic: metrics<=>abstraction
The predominant factor to engage and lead software engineering by is
"abstraction". So notation wise better: metrics<=>abstraction*
And to denote analyzing or summarizing the dialectic applied in whatever
context, from point 'a' to 'b': a,b{ metrics<=>abstraction*
Discrete points: a,b; l,q{ metrics<=>abstraction*
Have at your own meaningful fun!
Elliott
--
Global Plans + IID = part of an optimal approach
On Wed, 4 Feb 2004 23:36:17 -0500, "Universe"
<universe@tAkEcovadOuT.net> wrote:
>"Enumerative reasoning is only an adequate mental tool und...
(mapcar 'quote '("1" "2" "3" "4"))(mapcar 'quote '("1" "2" "3" "4")) returns
((quote "4") (quote "4") (quote "4") (quote "4"))
Interesting and (for me) unexpected. Because
(mapcar 'read '("1" "2" "3" "4")) returns
(1 2 3 4)
and
(mapcar 'princ '("1" "2" "3" "4")) gives
1234("1" "2" "3" "4")
Why isn't (mapcar 'quote '("1" "2" "3" "4")) returning
((quote "1") (quote "2") (quote "3") (quote "4"))
Tom Haws
www.hawsedc.com
Probably has to do with the fact that 'arg and (quote arg) are equivalent,
and LISP gets confused by the construct 'quote, which is about the same as
(quote (quote arg)). But I don't pretend to know all of the mechanics of the
error; the results are somewhat different in R14, BTW:
Command: (mapcar 'quote '("1" "2" "3" "4"))
((<Subr: #22e3e40> "4") (<Subr: #22e3e40> "4") (<Subr: #22e3e40> "4")
(<Subr:
#22e3e40> "4"))
___
"Tom Haws" <hawstom@despammed.com> wrote in message
news:77317472.0309160733.45ea9d8c@posting.google.com...
> (mapcar 'quote '("1" "2" "3"...
"for" with "else"?While trying to print a none empty list, I accidentaly put an "else"
statement with a "for" instead of "if". Here is what I had:
if ( len(mylist)> 0) :
for x,y in mylist:
print x,y
else:
print "Empty list"
which was supposed to be:
if ( len(mylist)> 0) :
for x,y in mylist:
print x,y
else:
print "Empty list"
Is this to be expected?
(python 2.2.2)
++++++++++++++++++++++++++++++=
>>> for x in range(5):
.... print x*x
.... else:
.... print "done"
....
0
1
4
9
16...
"A" is not equal "A"?I was trying to convert String Array to String A through cycle and than compare the result with String B but eventhough results were the same it returned false.
I'am working in BlueJ 3.1.0
Code is:
public boolean Method ()
{
String[] Example = {"a","b","c"};
String A = "";
String B = "abc"
for (int i = 0; i<3 ; i++)
{
A = A + Example[i];
}
if (A == B)
{
return true;
}
}
never got true...
I appreciate any suggestions how to solve this
Den 08.04.2014 10:06, skrev 245dav@gmail.com:...
Re: "out" and "in out""no reliable initial value" means, you cannot rely on the value, but it may have a value. This depends on the parameter passing mechanism, which is _not_ related to the parameter mode (contrary to what many people think).
So the parameter mode is there (nearly) solely for the information of the reader. The parameter passing mechanism for all kinds of parameters is defined in the RM. There are parameters passed by copy (in and out), by reference; for some it is explicitly left undefined.
In your case, the passing mechanism is by reference, so you get what you get. But don't rely...
" | " and "~" on solarishi,
someone know how configure the input keyboard.
when i want "|" on the term i have "^\"
when i want "~" i have "^^".
someone can help me ?
Thanks
gege1234 wrote:
> hi,
>
> someone know how configure the input keyboard.
> when i want "|" on the term i have "^\"
> when i want "~" i have "^^".
>
> someone can help me ?
>
> Thanks
man xmodmap
Hope this helps
--
Axel
i have try "loadkeys" and my keyboard became as before
thanks
...
How to change "/" to "\"Now, the output as below
/a/b/c.txt
b/c.txt
x:/b/c.txt , Need to change x:\b\c.txt
#!/bin/ksh
# echo.ksh
a=/a/b/c.txt
echo $a
echo ${a#/*/}
y=`echo x:/${a#/*/} | tr -s '/' '\'`
echo $y
moon wrote:
> Now, the output as below
>
> /a/b/c.txt
> b/c.txt
> x:/b/c.txt , Need to change x:\b\c.txt
>
>
> #!/bin/ksh
> # echo.ksh
> a=/a/b/c.txt
> echo $a
> echo ${a#/*/}
> y=`echo x:/${a#/*/} | tr -s '/' '\'`
> echo $y
>
>
One escape necessary:
echo x:/${a#/*/} | tr -s '/' '\\'
Two escapes necessar...
"==" is NOT TRUE "==", WHY?[CODE START]
x=5;
y=8;
if (x + y + 1E-15 == 13)
a = 3
else
a = 8
end
[CODE END]
When x + y + 1E-15, the code above returns a = 8.
When x + y + 1E-16, the code above returns a = 3.
Why? Kindly advise. Thanks.
"onemilimeter Chen" <onemm@example.com> wrote in message
<g7adrj$5tr$1@fred.mathworks.com>...
> [CODE START]
> x=5;
> y=8;
> if (x + y + 1E-15 == 13)
> a = 3
> else
> a = 8
> end
> [CODE END]
>
> When x + y + 1E-15, the code above returns a = 8.
> When x + y + 1E-16, the code above returns a = 3.
>
> Why? ...