Does it need a ";" at the very after of "if" and "for"
write code like: int main(void) { int a=10; if(a<20) {} } Compiler ok on dev-cpp . don't we have to add a ";" after if statement? marsarden said: > write code like: > > int main(void) > { > int a=10; > if(a<20) > {} > } > > Compiler ok on dev-cpp . don't we have to add a ";" after if > statement? The syntax for 'if' is: if(expression) statement There is no semicolon after the ) but before the statement. The statement is either a normal statement (which can be empty), ending in a semicolon:- if(expr) ...

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about "++" and "--"
why this program snippet display "8,7,7,8,-7,-8" the program is: main() { int i=8; printf("%d\n%d\n%d\n%d\n%d\n%d\n",++i,--i,i++,i--,-i++,-i--); } > why this program snippet display "8,7,7,8,-7,-8" Ask your compiler-vendor because this result is IMHO implementation-defined. Check this out: http://www.parashift.com/c++-faq-lite/misc-technical-issues.html#faq-39.15 http://www.parashift.com/c++-faq-lite/misc-technical-issues.html#faq-39.16 Regards, Irina Marudina fxc123@gmail.com wrote: > why this program snippet display "8,7,7,8,-7,-8&q...

"out" and "in out"
Hi i found the following explaination: In Ada, "in" parameters are similar to C++ const parameters. They are effectively read-only within the scope of the called subprogram. Ada "in out" parameters have a reliable initial value (that passed in from the calling subprogram) and may be modified within the scope of the called procedure. Ada "out" parameters have no reliable initial value, but are expected to be assigned a value within the called procedure. What does "have no reliable initial value" mean when considering the "out" parameter? By c...

"If then; if then;" and "If then; if;"
I have a raw data set which is a hierarchical file: H 321 s. main st P Mary E 21 F P william m 23 M P Susan K 3 F H 324 S. Main St I use the folowing code to read the data to creat one observation per detail(P) record including hearder record(H): data test; infile 'C:\Documents and Settings\retain.txt'; retain Address; input type $1. @; if type='H' then input @3 Address $12.; if type='P' then input @3 Name $10. @13 Age 3. @16 Gender $1.; run; but the output is not what I want: 1 321 s. main H 2 321 s. main P Mary E 21 F 3 321 s...

why "::", not "."
Why does the method of modules use a dot, and the constants a double colon? e.g. Math::PI and Math.cos -- Posted via http://www.ruby-forum.com/. On Oct 26, 2010, at 01:48 , Oleg Igor wrote: > Why does the method of modules use a dot, and the constants a double > colon? > e.g. > Math::PI and Math.cos For the same reason why inner-classes/modules use double colon, because = they're constants and that's how you look up via constant namespace. Math::PI and ActiveRecord::Base are the same type of lookup... it is = just that Base is a module and PI is a float....

"my" and "our"
Hi, while testing a program, I erroneously declared the same variable twice within a block, the first time with "my", the second time with "our": { my $fz = 'VTX_Link'; .... ( around 200 lines of code, all in the same block) our $fz = 'VTX_Linkset'; ... } So the initial contents of the $fz declared with "my" is lost, because "our" creates a lexical alias for the global $fz, thus overwriting the previous "my" declaration. It was my error, no question. But I wonder why Perl doesn't mention this - even with "use s...

"/a" is not "/a" ?
Hi everybody, while testing a module today I stumbled on something that I can work around but I don't quite understand. >>> a = "a" >>> b = "a" >>> a == b True >>> a is b True >>> c = "/a" >>> d = "/a" >>> c == d True # all good so far >>> c is d False # eeeeek! Why c and d point to two different objects with an identical string content rather than the same object? Manu Emanuele D'Arrigo wrote: >>>> c = "/a" >>>&...

"or" and "and"
Hi, I'm just getting to discover ruby, but I find it very nice programming language. I just still don't understand how the "or" and "and" in ruby... I was playing with ruby and for example made a def to print Stem and Leaf plot (for those who didn't have a statistics course or slept on it, e.g. http://cnx.org/content/m10157/latest/) Here is the Beta version of it: class Array def n ; self.size ; end def stem_and_leaf(st = 1) # if st != (2 or 5 or 10) then ; st = 1 ; end k = Hash.new(0) self.each {|x| k[x.to_f] += 1 } k = k.sort{|a, b| a[0].to_f <=&g...

"In" "Out" and "Trash"
I just bought a new computer and I re-installed Eudora Light on my new computer. But when I open Eudora, the "In", "Out" and "Trash" links are not on the left side of the screen the way they were on my old computer. How can I get these links back on the left side of the screen? Thank you. On 25 Mar 2007 09:49:22 -0700, "abx" <abfunex@yahoo.com> wrote: >I just bought a new computer and I re-installed Eudora Light on my new >computer. But when I open Eudora, the "In", "Out" and "Trash" links >are ...

A problem about "[ ]" "( )" "="
I want to read several images saved in a director,and give them to I1,I2 ,I3....,using the following codes: filelist=dir(['c:\MATLAB701\work\...\*.jpg']); for i=1 :length(filelist) I=imread(fullfile('c:\MATLAB701\work\...',filelist(i).name)); end; but failed. Then I used I(i)=imread... ,still failed. How could I do? "John" <mailofww@126.com> wrote in message news:ef19e12.-1@webx.raydaftYaTP... >I want to read several images saved in a director,and give them to > I1,I2 ,I3....,using the following codes: > filelist=dir(['c:\MATLAB701\work\.....

When to use "." and when to use "!"
I'm still confused about this and I can't find anywhere that explains it properly. I have the MS book "Access 2003" in front of me and I'm reading Part 5 about VB and so on. It's telling me about how to refer to a specific database and has the example:- Dim dbMyDb As DAO.Database Set dbMyDb = DBEngine.Workspaces(0).Databases(0) but, but, but, but - what do those dots (periods, full stops, call them what you will) mean? (OK, it appears to be the same usage as C/C++/Java when referring to class/structure members, but I wish it would tell me that somewhere) ...

help with "timefmt" and "using"...
Hi, is it possible to plot a data file like the following fragment without rebuild the archive? #DATE TIME-BEG TIME-END VALUE 7/03/2001 15:15:00 16:15:00 40115 7/03/2001 16:15:00 17:15:00 39960 7/03/2001 17:15:00 18:15:00 39990 8/03/2001 09:15:00 10:15:00 39985 8/03/2001 10:15:00 11:15:00 39855 8/03/2001 11:15:00 12:15:00 40310 I need to use as X data the 1st and the 3th columns, Y the last. I've spent a lot of time to try but with no result... Thanks a lot!!! Ciao, Francesco. Francesco <odiolaspam@tin.it> wrote: > Hi, > is it possible to plot a data file like the following fragment > without rebuild the archive? Sort of. You'll have to filter the file, but you can do that on-the-fly if you're on Unix or something sufficiently like it: plot '< awk "{print $1,$3,$4}" datafile' using 1:3 For other than timefmt data, that wouldn't be so much of a hassle, but unfortunately, the strptime() function that is the bases of 'set timefmt' offers no way of ignoring parts of the input. -- Hans-Bernhard Broeker (broeker@physik.rwth-aachen.de) Even if all the snow were burnt, ashes would remain. On 23 Oct 2003 09:01:23 GMT, Hans-Bernhard Broeker <broeker@physik.rwth- aachen.de> wrote: > if you're on Unix or something sufficiently like it: > > plot '< awk "{print $1,$3,$4}" datafile' using 1:3 > > For other than timefmt data...

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puts "\\".gsub("\\", "\\\\")
Hello, I have a mini-ruby quiz. Guess what this line of code writes to the console, then try it for yourself: puts "\\".gsub("\\", "\\\\") Why is that so? Martin From: martinus [mailto:martin.ankerl@gmail.com]=20 # Hello, I have a mini-ruby quiz. Guess what this line of code writes to # the console, then try it for yourself: # puts "\\".gsub("\\", "\\\\") puts "\\".gsub("\\", "\\\\") \ #=3D> nil # Why is that so? faq. escaping the escape in sub/gsub. search the archives. maybe you want somethin...

Question about "sprintf" "@" "do for"
Hello, this works: A1=3D1 A2=3D2 A3=3D3 i=3D1 vari=3Dsprintf("A%.f",i) print vari,"=3D",@vari i=3Di+1 vari=3Dsprintf("A%.f",i) print vari,"=3D",@vari i=3Di+1 vari=3Dsprintf("A%.f",i) print vari,"=3D",@vari do for [i=3D1:3]{ vari=3Dsprintf("A%.f",i) print vari } But I want to have "print vari,"=3D",@vari" in the loop. But it dosen't=20 work. Why can't I use "print vari,"=3D",@vari" in the loop? Is there a=20 solution for? J=C3=B6rg Jörg ...

like using "=..", "functor", "arg".
Hello, I must resolve the following problem: To define "=.." in terms of "functor" and "arg" and defining "functor" and "arg" in terms of "=..". I have tried to define "=..": input T = f(a,b,c). output L = [f,a,b,c]. term(T,L):- term(T,0,L). term(T,1,T). term(T,N,[F,A|L]):- length([A|L],M), functor(T,F,M), N1 is N-1, N1<M, arg(N1,T,A), term(T,N1,L). Someone can help me to resolve the problem? thanks. H...

when should one use "and" and "or"
Hi All, just got hit w the ff > case > when x==1 or x==2 > print "yeoh!" > end SyntaxError: compile error (irb):17: syntax error, unexpected kOR, expecting kTHEN or ':' or '\n' or ';' when x==1 or x==2 ^ "or" and "and" both exhibit the behaviour in ruby1.8/1.9. workaround 1 put parens around the condition (not again) 2 replace or/and with ||/&& i believe there are other similar quirks when using "and/or".. has ruby relegated the use of "and/or"....? best regar...

Do I need "self" and "other"?
Hi, I found one example which defines the addition of two vectors as a method of a class. It looks like that: class Vector: def __add__(self, other): data = [] for j in range(len(self.data)): data.append(self.data[j] + other.data[j]) return Vector(data) In this example one uses "self" and "other". Does one really need to use this words? And, if yes, why? I have replaced "self" by "x" and "other" by "y" and everything looks OK. Is it really OK or I can have some problem in some cases? Thank you! Kurda Yon wrote...

help to pass from "." to ","
Hi alls, I sent a message some time ago for ask you how can I read a .txt file. I solved that problem and I discovered that the only command that I need is "read". Now I Have another problem, I searched on the help and online but I didn't find out something usfeull. Well, because scilab separe decimal part with the sign "." and in this file there are numbers whos decimal part is separed with "," I'd like to tell to scilab something like "well, now the symbol "," for you is a point "."". So that I can read correctly all numbers in the file... Thanks for your attemption and sorry for my english > Hi alls, I sent a message some time ago for ask you how can I read > a .txt file. I solved that problem and I discovered that the only > command that I need is "read". Now I Have another problem, I searched > on the help and online but I didn't find out something usfeull. > Well, because scilab separe decimal part with the sign "." and in this > file there are numbers whos decimal part is separed with "," I'd like > to tell to scilab something like "well, now the symbol "," for you is > a point "."". So that I can read correctly all numbers in the file... Sorry, in my previous answer suggesting fscanfMat I had overlooked that your data contain commas. Looking at these data it seems they are actually i...

Invalid use of "." "!"
In writing a sql statement I get the error "invalid use of "." "!"......... this is apparently coming because the where clause of the sql statemt refers to a combo box with sales persons names in it. All the names are listed first initial followed by a "." and last name. I am assuming the error i am getting is coming from the "." in the combo box. How do I get around the invalid use of the "." ? Thanks Never mind..... didnt have enough quotation marks. "Learning" <texson552000@yahoo.com> wrote in message news:DQELg....

when to use "conv2", when to use "fft"->"multiplication"->"ifft"?
Hi all, I am doing 2D image filtering with sometimes filter size larger than image size. I am wondering which of the following scheme is the fastest, using Matlab: 1) conv2, 2D convolution directly; 2) conv2, but decompose the filter into two separable filters and then conv2 will first convolve along X axis and then convolve along Y axis; 3) fft2, multiplication, ifft2, all in 2D domain; 4) fft, multiplication, ifft, all in 1D case and work on convolutions of separable filters along X axis and Y axis; (similar to 2, but do 1D convolution all in frequency domain). Images and filters are...