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#### how to "(1-3*x^2)/(1-3*x+x^2+2*x^3) => 1/(1-2*x) + x/(1-x-x^2)"?

```hi

normal(1/(1-2*x) + x/ (1-x-x^2),expanded);
1/(1-2*x) + x/(1-x-x^2) => (1-3*x^2)/(1-3*x+x^2+2*x^3)
how to do the reverse?

``` 0  dillogimp
4/9/2007 12:48:38 PM comp.soft-sys.math.maple  4344 articles. 3 followers. 1 Replies 1786 Views Similar Articles

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```dillogimp@gmail.com writes:

>  normal(1/(1-2*x) + x/ (1-x-x^2),expanded);
> 1/(1-2*x) + x/(1-x-x^2) => (1-3*x^2)/(1-3*x+x^2+2*x^3)
> how to do the reverse?

convert(%,parfrac,x);

--
Joe Riel
``` 0  Joe
4/9/2007 1:46:44 PM Similar Artilces:

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