Log[1/E^-.5] � .5
Or if you need to,
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> On Sun, 27 Nov 2005 08:24:53 +0000 (UTC), Bob Hanlon
> >The output that you want is "unstable", i.e., Mathematica automatically
> >converts it.
> I have another question if you don't mind.
> I'm trying to just check and see if I got a whole bunch of
> even-numbered study exercises right on exponents and natural logs.
> The answers to the odds are in the book.
> As an example, LN(1/e^2) equals what?
> My answer is -1/2.
> In mathematica, I tried Simplify[LN(1/e^2)] and it just spit the same
> thing out as the output. I also tried a couple of variations of
> Solve[LN[1/e^2] = X] with essentially the same result
> How would you get Mathematica to verify that the answer is -1/2.
> Thanks a lot.