I have the following parameters are trying to design a simple band pass filter by zero pole placement and need some help please
nyquist frequency = 800 Hz
pass band = 300 Hz
central frequency = 100 Hz
I need to plot the frequency response of the IIR filter by two polynomials...one for frequency and another for magnitude....
spent couple of hours on it but not going anywhere...help please
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PinkLab
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4/27/2010 12:30:23 PM |
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On 27 apr, 14:30, "PinkLab " <pink...@pinklab.com> wrote:
> I have the following parameters are trying to design a simple band pass filter by zero pole placement and need some help please
>
> nyquist frequency = 800 Hz
> pass band = 300 Hz
> central frequency = 100 Hz
>
> I need to plot the frequency response of the IIR filter by two polynomials...one for frequency and another for magnitude....
>
> spent couple of hours on it but not going anywhere...help please
You need to get back to basics:
1) If the upper cut-off is 300 Hz and the 'central frequency'
is 100 Hz, the bandwidth becomes...?
2) The IIR is expressed in terms of two ploynomials, whereas
frequency and magnitude responses are not. You are mixing
up the terms.
If this is some kind of preparation for some exam (it's that
time of year) you might be better off skipping this particular
exam this time around, and take it again in the summer, and
instead focus on the subjects you have an actual chance of
passing.
Rune
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Rune
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4/27/2010 12:46:00 PM
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@Rune: this is a task in matlab...not sure what will be the bandwidth then? could you be more helpful than just saying to drop this for now? thanks
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PinkLab
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4/27/2010 12:55:21 PM
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On 27 apr, 14:55, "PinkLab " <pink...@pinklab.com> wrote:
> @Rune: this is a task in matlab...not sure what will be the bandwidth then? could you be more helpful than just saying to drop this for now? thanks
No, I can't. This is about understanding the veruy basics of
filter design. You are weeks of work away from even stating a
comprehensable question. So either drop it, or go back to basics
and start reading (and contemplating!) the required material.
Rune
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Rune
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4/27/2010 1:12:22 PM
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