Hi,
I have two arrays:
date_array1 = [ 20101201; 20091201; 20091101; 20100101 ];
date_array2 = [ 20081201; 20101201; 20091201; 20061201; 20100101 ];
I basically want to compare the two arrays and get only the elements of second array date_array2 that are not present in date_array1.
So in the above example I want to get a result of:
20081201
20061201
Either of the arrays may be larger than the other. In my actual problem both the arrays are huge, so I was wondering if there was a smart efficient way to do it.
Thanks in advance.
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jay
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8/30/2010 5:15:19 PM |
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"jay jay" <jay.oberoi@yahoo.com> wrote in message <i5gov7$d8s$1@fred.mathworks.com>...
> Hi,
>
> I have two arrays:
>
> date_array1 = [ 20101201; 20091201; 20091101; 20100101 ];
>
> date_array2 = [ 20081201; 20101201; 20091201; 20061201; 20100101 ];
>
> I basically want to compare the two arrays and get only the elements of second array date_array2 that are not present in date_array1.
>
> So in the above example I want to get a result of:
> 20081201
> 20061201
>
> Either of the arrays may be larger than the other. In my actual problem both the arrays are huge, so I was wondering if there was a smart efficient way to do it.
>
> Thanks in advance.
doc setdiff
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Andy
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8/30/2010 5:27:36 PM
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Great, thanks!
"Andy " <myfakeemailaddress@gmail.com> wrote in message <i5gpm8$1e8$1@fred.mathworks.com>...
> "jay jay" <jay.oberoi@yahoo.com> wrote in message <i5gov7$d8s$1@fred.mathworks.com>...
> > Hi,
> >
> > I have two arrays:
> >
> > date_array1 = [ 20101201; 20091201; 20091101; 20100101 ];
> >
> > date_array2 = [ 20081201; 20101201; 20091201; 20061201; 20100101 ];
> >
> > I basically want to compare the two arrays and get only the elements of second array date_array2 that are not present in date_array1.
> >
> > So in the above example I want to get a result of:
> > 20081201
> > 20061201
> >
> > Either of the arrays may be larger than the other. In my actual problem both the arrays are huge, so I was wondering if there was a smart efficient way to do it.
> >
> > Thanks in advance.
>
> doc setdiff
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Reply
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jay
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8/30/2010 5:43:05 PM
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