hi , I am using the MIT-BIH Arrhythmia Database and was asked to get 10 consecutive minutes, and i did and then three colums, first for time, second for MLII and third for V5 and ended up with these
x = txt(1:86401,1);
y = txt(1:86401,2);
z = txt(1:86401,3);
hold on;
plot(x,y)
plot(x,z)
but i am asked to determine number of heart beats and duration of the time interval between successive heart beats, and this is without using a filter, how would i do that since data number is so large and heartbeats are very small?
thanx so much
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gedaa
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3/28/2011 9:07:05 AM |
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"gedaa " <ghaida8686@gmail.com> wrote in message <impj3p$b0p$1@fred.mathworks.com>...
> hi , I am using the MIT-BIH Arrhythmia Database and was asked to get 10 consecutive minutes, and i did and then three colums, first for time, second for MLII and third for V5 and ended up with these
>
> x = txt(1:86401,1);
> y = txt(1:86401,2);
> z = txt(1:86401,3);
> hold on;
> plot(x,y)
> plot(x,z)
>
> but i am asked to determine number of heart beats and duration of the time interval between successive heart beats, and this is without using a filter, how would i do that since data number is so large and heartbeats are very small?
>
> thanx so much
Have you tried using Fourier analysis?
Wayne
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Wayne
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3/28/2011 10:20:04 AM
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"gedaa " <ghaida8686@gmail.com> wrote in message <impj3p$b0p$1@fred.mathworks.com>...
> hi , I am using the MIT-BIH Arrhythmia Database and was asked to get 10 consecutive minutes, and i did and then three colums, first for time, second for MLII and third for V5 and ended up with these
>
> x = txt(1:86401,1);
> y = txt(1:86401,2);
> z = txt(1:86401,3);
> hold on;
> plot(x,y)
> plot(x,z)
>
> but i am asked to determine number of heart beats and duration of the time interval between successive heart beats, and this is without using a filter, how would i do that since data number is so large and heartbeats are very small?
>
> thanx so much
Hi,
you could try findpeaks. I suggest working on a 30 sec - 1 min portion first until you get a handle of the function's option and after that apply it to the whole signal. You should also take into consideration that an irregular / pseudo periodic signal (which one may expect in this case) could cause abnormal results, so it's up to you to make it reliable.
Hope it helps.
Regards,
Florin
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Florin
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3/28/2011 6:50:06 PM
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2 Replies
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