Finding n largest values in a matrix

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I've been programming in Matlab for quite a while now, but recently I ran into a problem that I can't solve in a neat and efficient way. I have a 2D matrix A (lets say 32x32) and a vector B (lets say its length is 16). Now I want to find 16 largest values in matrix A. Then I want to add first component of vector B to largest element in A, second component of B to second largest element in A and so on. Can anyone give me a hint how can I do it without using time consuming iterative algorithm?
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Reply Jan 1/11/2010 11:24:03 AM

Are you sure those are really the sizes of your matrices?  Because I
don't really consider nanoseconds "time consuming."  Now if they were
thousands of elements in each direction, then it could be time
consuming.  Anyway, did you look at sort()?
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Reply ImageAnalyst 1/11/2010 11:39:16 AM


Dear Jan!

> I've been programming in Matlab for quite a while now, but recently I ran into a problem that I can't solve in a neat and efficient way. I have a 2D matrix A (lets say 32x32) and a vector B (lets say its length is 16). Now I want to find 16 largest values in matrix A. Then I want to add first component of vector B to largest element in A, second component of B to second largest element in A and so on. Can anyone give me a hint how can I do it without using time consuming iterative algorithm?

Have you seen Bruno's MinMax selection function?
http://www.mathworks.com/matlabcentral/fileexchange/23576

Usually this is much faster than SORT.

Good luck, Jan
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Reply Jan 1/11/2010 12:03:05 PM

Size of matrices is just an example - they will be bigger (1024x1024) and this operation will be run thousands of times. Even if it weren't I still want to create my code that is as fast as possible :)

I'm afraid sort() (or sortrows() ) won't solve my problem. At least I don't see how I could use these functions. sort()/sortrows() can give me indices of elements in a column/row, but it's possible that 2-nd largest element in column/row 1 is greater than largest element in column/row 2. I need something that gives global results.
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Reply Jan 1/11/2010 12:12:02 PM

Size of matrices is just an example - they will be bigger (1024x1024) and this operation will be run thousands of times. Even if it weren't I still want to create my code that is as fast as possible :)

I'm afraid sort() (or sortrows() ) won't solve my problem. At least I don't see how I could use these functions. sort()/sortrows() can give me indices of elements in a column/row, but it's possible that 2-nd largest element in column/row 1 is greater than largest element in column/row 2. I need something that gives global results.
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Reply Jan 1/11/2010 12:13:03 PM

"Jan " <fremenzone@poczta.onet.pl> wrote in message <hif4ii$rur$1@fred.mathworks.com>...
> Size of matrices is just an example - they will be bigger (1024x1024) and this operation will be run thousands of times. Even if it weren't I still want to create my code that is as fast as possible :)
> 
> I'm afraid sort() (or sortrows() ) won't solve my problem. At least I don't see how I could use these functions. sort()/sortrows() can give me indices of elements in a column/row, but it's possible that 2-nd largest element in column/row 1 is greater than largest element in column/row 2. I need something that gives global results.

What about this

% data
  n = 4 ; A = magic(n) ; % a large matrix of size n-by-n
  m = 4 ; % replace m highest values with elements of B
  B = -(1:m) ; 

%engine
  [si,si] = sort(A(:),'descend') ;
  A(si(1:m)) = B

hth
Jos
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Reply Jos 1/11/2010 12:59:05 PM

Works like a charm! Thanks very much.
I didn't know that I can convert 2D matrix to a vector using A(:). 
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Reply Jan 1/11/2010 1:57:04 PM

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