how to concisely choose the first element in a vector modified by a conditional statement?

Hi, I need to choose the first element of a vector that's modified by a conditional statement. For example, suppose: I = [1 2 3 4]; R = logical( [0 1 0 1] ); Then I(R) returns [2 4]. What I need to do is to find "2" and assign it to a new variable, which has to be a one element. I can do the following: t = I(R); t = t(1); But this is not concise enough. I just hope there is a better way to do this. For example, something like in C, "I(R)[1]", sort of things. However, this syntax does not work in Matlab. Thanks!

"Pinpress" <nospam__@yahoo.com> wrote in message <hte45u$rqt$1@fred.mathworks.com>... > Hi, > > I need to choose the first element of a vector that's modified by a conditional statement. For example, suppose: > > I = [1 2 3 4]; > R = logical( [0 1 0 1] ); > > Then I(R) returns [2 4]. What I need to do is to find "2" and assign it to a new variable, which has to be a one element. I can do the following: > > t = I(R); t = t(1); > > But this is not concise enough. I just hope there is a better way to do this. For example, something like in C, "I(R)[1]", sort of things. However, this syntax does not work in Matlab. Thanks! NO... as has been discussed over and over, again, in this NG, contractions don't work in ML... one of the solutions d=1:4; dl=logical([0,0,1,1]); r=d(find(dl,1,'first')) % <- a horrible construct... % r = 3 us

Thanks us! Your replies are always good ... it is concise enough for me. "us " <us@neurol.unizh.ch> wrote in message <hte4ms$42h$1@fred.mathworks.com>... > "Pinpress" <nospam__@yahoo.com> wrote in message <hte45u$rqt$1@fred.mathworks.com>... > > Hi, > > > > I need to choose the first element of a vector that's modified by a conditional statement. For example, suppose: > > > > I = [1 2 3 4]; > > R = logical( [0 1 0 1] ); > > > > Then I(R) returns [2 4]. What I need to do is to find "2" and assign it to a new variable, which has to be a one element. I can do the following: > > > > t = I(R); t = t(1); > > > > But this is not concise enough. I just hope there is a better way to do this. For example, something like in C, "I(R)[1]", sort of things. However, this syntax does not work in Matlab. Thanks! > > NO... as has been discussed over and over, again, in this NG, contractions don't work in ML... > > one of the solutions > > d=1:4; > dl=logical([0,0,1,1]); > r=d(find(dl,1,'first')) % <- a horrible construct... > % r = 3 > > us

Pinpress wrote: > I need to choose the first element of a vector that's modified by a > conditional statement. For example, suppose: > > I = [1 2 3 4]; > R = logical( [0 1 0 1] ); > > Then I(R) returns [2 4]. What I need to do is to find "2" and assign it > to a new variable, which has to be a one element. I can do the following: > > t = I(R); t = t(1); t = I(find(R,1))

"Pinpress" <nospam__@yahoo.com> wrote in message news:hte45u$rqt$1@fred.mathworks.com... > Hi, > > I need to choose the first element of a vector that's modified by a > conditional statement. For example, suppose: > > I = [1 2 3 4]; > R = logical( [0 1 0 1] ); > > Then I(R) returns [2 4]. What I need to do is to find "2" and assign it to > a new variable, which has to be a one element. I can do the following: > > t = I(R); t = t(1); > > But this is not concise enough. Why? -- Steve Lord slord@mathworks.com comp.soft-sys.matlab (CSSM) FAQ: http://matlabwiki.mathworks.com/MATLAB_FAQ To contact Technical Support use the Contact Us link on http://www.mathworks.com

Hi Steven, As you can see, if I need to assign the first element to a variable, I need to have one more assignment statement. That's why I feel not concise enough. Not esthetically appealing to me. "Steven Lord" <slord@mathworks.com> wrote in message <htenrv$qic$1@fred.mathworks.com>... > > "Pinpress" <nospam__@yahoo.com> wrote in message > news:hte45u$rqt$1@fred.mathworks.com... > > Hi, > > > > I need to choose the first element of a vector that's modified by a > > conditional statement. For example, suppose: > > > > I = [1 2 3 4]; > > R = logical( [0 1 0 1] ); > > > > Then I(R) returns [2 4]. What I need to do is to find "2" and assign it to > > a new variable, which has to be a one element. I can do the following: > > > > t = I(R); t = t(1); > > > > But this is not concise enough. > > Why? > > -- > Steve Lord > slord@mathworks.com > comp.soft-sys.matlab (CSSM) FAQ: http://matlabwiki.mathworks.com/MATLAB_FAQ > To contact Technical Support use the Contact Us link on > http://www.mathworks.com >

"Pinpress" <nospam__@yahoo.com> wrote in message <hte45u$rqt$1@fred.mathworks.com>... > t = I(R); t = t(1); > > But this is not concise enough. I just hope there is a better way to do this. For example, something like in C, "I(R)[1]", sort of things. However, this syntax does not work in Matlab. Thanks! ============= What would be wrong with t=I(R(1));

"Pinpress" <nospam__@yahoo.com> wrote in message <htgo3c$d6v$1@fred.mathworks.com>... > That doesn't work: suppose R = logical([0 0 1 1]). > > "Matt J " <mattjacREMOVE@THISieee.spam> wrote in message > > > > > > What would be wrong with t=I(R(1)); ============== Sorry, you're right. Well, although it's off-label use, you could use my IndexableFunction class http://www.mathworks.com/matlabcentral/fileexchange/26570-direct-indexing-of-function-calls-oop-exercise It would work as follows: >> I=[1,2,3,4]; R=logical([0 1 0 1]); >> t=IndexableFunction(I); >> t{R}(1) %almost the syntax that you want ans = 2

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7/11/2012 2:36:18 PM