matlab program to find coordinate of sphere in a cube

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Hey hi everyone
I am new to Matlab and wanna write a code to find the coordinate x,y,z which can be used as a centre of 8 sphere of radius r=.015 which must lie inside a cube of .09*.09*.09.The spheres must not touch each other and should not touch the boundary so i calculate the distance between them and compared it to 2*.015 i dont know but there is something wrong with my loop can any one suggest what is going wrong



for i=1:8
    x(i)=rand(1,1)*.065; % will generate random number from 0 to .065
    y(i)=rand(1,1)*.065;
    z(i)=rand(1,1)*.065;
    if x(i)<.018        % to take care that they dont intersect boundary
        x(i)=x(i)+.015;
    end
    if y(i)<.018
        y(i)=y(i)+.015;
    end
    if z(i)<.018
        z(i)=z(i)+.015;
    end
end

% let r=.01 and thickness =.004 therefore distance between them <
% .014*2=.028~ .03 or R^2=.0009

for l=1:8
    for m=1:8
        
           if (l~=m)
                R=sqrt((x(l)-x(m))*(x(l)-x(m))+(y(l)-y(m))*(y(l)-y(m))+(z(l)-z(m))*(z(l)-z(m)));
                if(R<.03)  % R is the square of distance between them therefore should be <.0009
                    z(l)=z(l) +.001 -.001*R;
		           if z(l)>.085  % to take into account that it doesnot touch boundary
                       z(l)=z(l)-.015;
                   end
                   l=1;
                    m=1;
                end
		
           end
           
    end
end
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Reply crazyman 6/15/2010 6:34:10 PM


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