Now i'm assigned to use >>for loop / for function<< to list the index of every max elements.
EXAMPLE:
z = randint(10,10,100); %Z is a random generate 10 by 10 matrix
disp(z);
i=max(z,[],2);
disp(i); %Return the largest elements of z matrix from each row
Output:
z=
81 15 65 70 43 27 75 84 35 7
90 97 3 3 38 67 25 25 83 5
12 95 84 27 76 65 50 81 58 53
91 48 93 4 79 16 69 24 54 77
63 80 67 9 18 11 89 92 91 93
9 14 75 82 48 49 95 34 28 12
27 42 74 69 44 95 54 19 75 56
54 91 39 31 64 34 13 25 75 46
95 79 65 95 70 58 14 61 38 1
96 95 17 3 75 22 25 47 56 33
i=
84
97
95
93
93
95
95
91
95
96
And now, i need to use >>for loop / for function<< to list out the coordinate/index of the max elements in every row. Lets say we take the 1st element which is "84" , its coordinate/index is i=1, j=1 .So does anyone have any idea/clue for me to use "for loop/for function to list out the coordinate of every max elements from each row?"
Thank you~
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VIC
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11/30/2010 6:58:04 AM |
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Look at the second output argument of MAX()
Bruno
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Bruno
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11/30/2010 7:05:04 AM
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"Bruno Luong" <b.luong@fogale.findmycountry> wrote in message <id27n0$n69$1@fred.mathworks.com>...
> Look at the second output argument of MAX()
>
> Bruno
Thanks for your reply,
I'm not sure which one is the second output argument of MAX()
function [f,g] = patho(x)
Max = 500;
f = zeros(size(x,1),1);
g = zeros(size(x));
for k = 1:Max %k
arg = sin(pi*k^2*x)/(pi*k^2);
f = f + sum(arg,2);
g = g + cos(pi*k^2*x);
end
?
Matlab newbie *.*
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VIC
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11/30/2010 7:41:04 AM
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>
> I'm not sure which one is the second output argument of MAX()
>
[firstoutput secondouput] = max(yourmatrix)
Bruno
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Bruno
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11/30/2010 7:49:05 AM
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>
> [firstoutput secondouput] = max(yourmatrix)
>
> Bruno
Oh~i read the description in help,
[M, Indices] = max(DMObj1) returns Indices, the indices of the maximum value(s) in DMObj1, a DataMatrix object. If DMObj1 contains a vector of data, Indices is a positive integer. If DMObj1 contains a matrix of data, Indices is a vector containing the indices for the maximum value in each column (if Dim = 1) or row (if Dim = 2). If there are multiple maximum values in a column or row, the index for the first value is returned.
z = randint(10,10,100); %Z is a random generate 10 by 10 matrix
disp(z);
t=max(z,[],2);
disp(t); %Return the largest elements of z matrix from each row
By refer to the code above,
[t,indices]=max(z);
what is the indice means? Is it a number? When i replace the indices with number (For example, [t,10]=max(z);), it showed "Invalid used of '10' on the left side of the assignment"
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VIC
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11/30/2010 8:20:20 AM
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Is it possible to use >>for loop<< to find the index of the max element in each row? and how to access it?
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VIC
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11/30/2010 9:44:04 AM
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"VIC " <vicnsc@yahoo.com> wrote in message <id2c44$5ua$1@fred.mathworks.com>...
> >
> > [firstoutput secondouput] = max(yourmatrix)
> >
> > Bruno
>
> Oh~i read the description in help,
> [M, Indices] = max(DMObj1) returns Indices, the indices of the maximum value(s) in DMObj1, a DataMatrix object. If DMObj1 contains a vector of data, Indices is a positive integer. If DMObj1 contains a matrix of data, Indices is a vector containing the indices for the maximum value in each column (if Dim = 1) or row (if Dim = 2). If there are multiple maximum values in a column or row, the index for the first value is returned.
>
> z = randint(10,10,100); %Z is a random generate 10 by 10 matrix
> disp(z);
> t=max(z,[],2);
> disp(t); %Return the largest elements of z matrix from each row
>
> By refer to the code above,
>
> [t,indices]=max(z);
>
> what is the indice means? Is it a number? When i replace the indices with number (For example, [t,10]=max(z);), it showed "Invalid used of '10' on the left side of the assignment"
As Bruno stated before [firstoutput secondouput] = max(yourmatrix). The <secondoutput> is an output, hence you don't assign it a value, the <max> function assigns it, just like it assigns the max value to <t> in your code.
Try replacing <10> with a variable name and examining the contents. If you are still confused, try <doc ind2sub> and <doc max>
Jason
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Jason
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11/30/2010 11:41:04 AM
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6 Replies
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