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### remove rows with repeat numbers

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```Hi
how can i remove the rows with repeated digits in A in order to form new_A?

A =
72     81
51     67
33     33
25     24
50     50

new_A =

72     81
51     67
25     24

thanks
```
 0

```On 10/17/2010 9:32 PM, Kurt wrote:
> Hi
> how can i remove the rows with repeated digits in A in order to form new_A?
>
> A =
>       72     81
>       51     67
>       33     33
>       25     24
>       50     50
>
>
> new_A =
>
>                        72     81
>                        51     67
>                        25     24
>
> thanks

one way:

A =  [72     81;
51     67;
33     33;
25     24;
50     50]

A(find(arrayfun(@(i)length(unique(A(i,:))),1:size(A,1))==size(A,2)),:)

ans =
72    81
51    67
25    24

--Nasser
```
 0

```thanks nasser,

I have another issue. With the code below :

Please note that the function 'npermutek' can be found at:
http://www.mathworks.com/matlabcentral/fileexchange/11462-npermutek

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

A = [    1     4     7]

A = npermutek(A,2)
A= sort(A,2)
A =unique(A,'rows' )
A(find(arrayfun(@(i)length(unique(A(i,:))),1:size(A,1))==size(A,2)),:)

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

I get the following result, which is what I want:

ans =

1     4
1     7
4     7

However, if I increase the input A matrix to:

A = [    1     4     7;
1      4     5 ]

How can I obtain:

result =
1     4
1     7
4     7
1     4
1     5
4     5

Please note that the last 3 rows in the 'result ' matrix can be obtained if I use A = [    1     4     5] as the input in my code.

How can I get this result  ?

thanks a lot
kurt
```
 0

```Hi,

Can anyone suggest how I may address this problem? I am not sure but is a  'for loop' required for situations as these?

thanks
kurt
```
 0

```NPERMUTEK finds the permutations with repetition.  What you are finding is the combinations without repetition.  I would therefore use NCHOOSEK, a MATLAB built-in.

nchoosek( [ 1 4 7],2)
```
 0

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