f

#### Using "fsolve": How to control iteration using "residuals" and "norm of step"??

```Hello Everyone,

I am using fsolve to solve a system of linear equations and it&#8217;s working fine. However, I have a coupe of issues:

(i)	Even when the solution (alpha) converges, I am getting the message to choose a new point. I am guessing that it has to do with &#8220;norm of step&#8221; as probably the code is trying a smaller step.
I am using option like this:
options = optimset('Jacobian','on', 'algorithm', 'Levenberg-Marquardt','Display','iter-detailed', 'MaxFunEvals', 10000, 'MaxIter', 10000,'TolX',1e-6);

First-Order                    Norm of
Iteration  Func-count    Residual       optimality   Lambda           step
0           1    1.05324e+008       7.92e+009         0.01
1          13    9.11469e+007       7.41e+009       1e+009      0.0208017
2          14    7.82897e+007        6.9e+009       1e+008      0.0196052
3          16    6.67656e+007       6.41e+009       1e+009      0.0183924
&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;.

307         492      0.00279243       2.43e+004       1e+009   1.81153e-007
308         493      0.00275538       2.47e+004       1e+008   1.87256e-007
309         495      0.00272348       2.53e+004       1e+009   1.93836e-007
310         496      0.00269742       2.59e+004       1e+008   2.00901e-007
311         498      0.00267798       2.66e+004       1e+009   2.08456e-007
312         499      0.00266609       2.74e+004       1e+008   2.16513e-007
313         501      0.00266275       2.82e+004       1e+009   2.25082e-007
314         503      0.00244956       2.46e+004       1e+010   4.25771e-008
Optimizer appears to be converging to a minimum that is not a root:
Sum of squares of the function values exceeds the square root of
options.TolFun. Try again with a new starting point.

alpha =

0.0112    0.0800

fval =

-0.0275
-0.0231
0.0341

exitflag =

-2
(ii)	I do not need this much precision anyway and I guess that the function tolerance of .01 would be good enough for my purpose. However, when I try to set it like this:

options = optimset('Jacobian','on', 'algorithm', 'Levenberg-Marquardt','Display','iter-detailed', 'MaxFunEvals', 10000, 'MaxIter', 10000,'Tolfun',1e-2);

First-Order                     Norm of
Iteration  Func-count    Residual       optimality   Lambda      step
0           1    1.05324e+008       7.92e+009         0.01
1          13    9.11469e+007       7.41e+009       1e+009      0.0208017
2          14    7.82897e+007        6.9e+009       1e+008      0.0196052
3          16    6.67656e+007       6.41e+009       1e+009      0.0183924
4          17    5.65487e+007       5.93e+009       1e+008      0.0171724
5          19    4.75817e+007       5.48e+009       1e+009       0.015954
6          20    3.97842e+007       5.04e+009       1e+008      0.0147456
7          22    3.30609e+007       4.63e+009       1e+009      0.0135547
8          23    2.73085e+007       4.24e+009       1e+008      0.0123879
9          25    2.24219e+007       3.87e+009       1e+009      0.0112508
10          26    1.82982e+007       3.52e+009       1e+008      0.0101476
11          28    1.48402e+007       3.19e+009       1e+009     0.00908189
12          29    1.19583e+007       2.89e+009       1e+008     0.00805609
13          31    9.57163e+006        2.6e+009       1e+009     0.00707201
14          32    7.60831e+006       2.34e+009       1e+008     0.00613096
15          34    6.00542e+006       2.09e+009       1e+009     0.00523424
16          35    4.70846e+006       1.86e+009       1e+008     0.00438368
17          37    3.67066e+006       1.64e+009       1e+009     0.00358298
18          38    2.85223e+006       1.44e+009       1e+008     0.00284029
19          39    2.54305e+006       1.35e+009       1e+007     0.00658172
20          40    2.45261e+006       1.33e+009       1e+006     0.00889797
21          42    2.40947e+006       1.32e+009       1e+007     0.00936895
22          44    2.16844e+006       1.25e+009       1e+008     0.00637137
23          45    1.92317e+006       1.18e+009       1e+007      0.0055473
24          46    1.82623e+006       1.15e+009       1e+006     0.00722428
25          47      1.777e+006       1.14e+009       100000     0.00776316
26          50    1.74584e+006       1.13e+009       1e+007     0.00792976
27          52     1.5762e+006       1.07e+009       1e+008     0.00549951
28          53    1.40525e+006       1.01e+009       1e+007     0.00486917
29          54     1.3502e+006       9.92e+008       1e+006     0.00645609
30          55     1.3438e+006       9.94e+008       100000     0.00720752
Optimizer appears to be converging to a minimum that is not a root:
Sum of squares of the function values exceeds the square root of
options.TolFun. Try again with a new starting point.

alpha =

-0.0112    0.2191

fval =

1.0e+003 *

0.0169
-1.0535
0.4834

exitflag =

-2

Of course, the value of alpha has not converged. So, it seems that I am not using &#8220;tolfun&#8221; the way I intend to use it to control residuals. As you may remember, I am solving a series of nonlinear equations.

I would really appreciate if someone tells me how to control &#8220;residuals&#8221; and &#8220;norm of steps&#8221;.

Also, is it possible to display the value of alpha during EACH iteration using 'Display','iter-detailed'?

Any help would be appreciated.

Thanks,
DK
```
 0
9/24/2009 6:55:20 PM
comp.soft-sys.matlab 211266 articles. 25 followers. lunamoonmoon (257) is leader.

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Used PERLE 494 AS/400 controller for sale. PRICE : 400,00 euros. uzados@gmail.com +351 967443880 On Feb 28, 9:25 pm, "Uzados" <uza...@gmail.com> wrote: > Used PERLE 494 AS/400 controller for sale. > > PRICE : 400,00 euros. > > uza...@gmail.com > +351 967443880 Is this the same unit you've been trying to sell for 4 years? Just keeps adding more single quotes to the subject line :-) Regards, Richard Schoen RJS Software Systems Inc. "Providing Your....iNFORMATION NOW!" Email: richard@rjssoftware.com Web Site: http://www.rjssoftware.com Tel: (952) 898-3038 Fax: (952) 898-1781 Toll Free: (888) RJSSOFT "Buster" <spitcher@minas.ns.ca> wrote in message news:1172725718.798152.65100@v33g2000cwv.googlegroups.com... > On Feb 28, 9:25 pm, "Uzados" <uza...@gmail.com> wrote: >> Used PERLE 494 AS/400 controller for sale. >> >> PRICE : 400,00 euros. >> >> uza...@gmail.com >> +351 967443880 > > Is this the same unit you've been trying to sell for 4 years? > ...

svmon "virtual" vs. "work in use"
Hello, on nearly all of my systems, those both values are more or less the same, f.e.: size inuse free pin virtual memory 1572864 496929 1075935 82182 173205 pg space 1048576 696 work pers clnt lpage pin 82182 0 0 0 in use 173218 323711 0 0 Just 213 pages more at "work in use". I never noticed big differences on my nodes regarding these values, thats why I never cared about the difference. Now, however, I noticed that on one system virtual is double, sometimes 3x as much as "work in use". This is a mq-system where we have application-related problems, thats why I am interested in this "special behaviour". What are the differences between those values? What is part of virtual, but not "work in use" and vice versa? All I know is that the text-segment is part of "virtual", but not part of "work in use". Regards, Holger ...

use "old" .so-files with "new" compiler?