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Re: Puzzle: Converting 1-10 to 1,2,3,4,5,6,7,8,9,10 #3

Very nice!

-Mary
  ----- Original Message -----=20
  From: Toby Dunn=20
  To: SAS-L@LISTSERV.UGA.EDU=20
  Sent: Friday, October 03, 2008 3:55 PM
  Subject: Re: Puzzle: Converting 1-10 to 1,2,3,4,5,6,7,8,9,10


  Data _Null_ ;
  Length NewString $ 200 ;
  String =3D '1-10,21,22,30-35,40,41' ;

  Do I =3D 1 To ( 1 + CountC( String , ',' ) ) ;

    TempA =3D Scan( String , I , ',' ) ;

    If Find( TempA , '-' ) Then Do ;
      Start =3D Input( Scan( TempA , 1 , '-' ) , Best12. ) ;
      Stop  =3D Input( Scan( TempA , 2 , '-' ) , Best12. ) ;

      Do K =3D Start To Stop ;
        NewString =3D CatX( ',' , NewString , K ) ;
      End ;
    End ;
    Else Do ;
      NewString =3D CatX( ',' , NewString , TempA ) ;
    End ;

  End ;

  Put NewString=3D ;

  Run ;


  On Fri, 3 Oct 2008 16:27:44 -0400, Paul Walker <walker.627@OSU.EDU> =
wrote:

  >What is the best way to convert a string like 1-10 to a string like
  >1,2,3,4,5,6,7,8,9,10?  The string is stored as a variable in a =
datastep.
  >I am looking for a function that could be called like this maybe.
  >
  >data _null_;
  >  string =3D '1-10';
  >  newstring =3D function(string);
  >run;
  >
  >Add a twist to the puzzle: what if I mixed and matched.  For example, =
a
  >string 1-10,21,22,30-35,40,41.
  >
  >data _null_;
  >  string =3D '1-10,21,22,30-35,40,41';
  >  newstring =3D function(string);
  >run;
  >
  >newstring =3D 1,2,3,4,5,6,7,8,9,10,21,22,30,31,32,33,34,35,40,41
  >
  >You get the idea.  Any suggestions for the function?
  >
  >- Paul
0
mlhoward (1803)
10/3/2008 8:59:11 PM
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Re: Puzzle: Converting 1-10 to 1,2,3,4,5,6,7,8,9,10 #10
This is absurd - but uses the call execute as I intended.... data strings; String='1-10,21,22,30-35,40,43'; output; String='7-8,11-22,26-35,36'; output; String='9-20,31,32,34-35,41,44'; output; run; Data _Null_; set strings; call execute ( "proc format;value numstr " ||String||"='Nums';run;"); if _n_=1 then call execute (" Data NewStrings(drop=_:); Length NewString $ 200 ; if _n_=1 then do; Do _K = input(Scan('"||String||"',1,',-'),best12.) To input(Scan('"||String||"',-1,',-'),best12.); If put(_K,numstr.)='Nums' then NewString=CatX(',',NewString,_K) ; End; output; End; Run;"); else call execute (" Data NewStrings(drop=_:); Length NewString $ 200 ; if _n_=1 then do; Do _K = input(Scan('"||String||"',1,',-'),best12.) To input(Scan('"||String||"',-1,',-'),best12.); If put(_K,numstr.)='Nums' then NewString=CatX(',',NewString,_K) ; End; output; End; set newstrings; output; Run;"); Run; Paul Choate DDS Data Extraction (916) 654-2160 -----Original Message----- From: SAS(r) Discussion [mailto:SAS-L@LISTSERV.UGA.EDU] On Behalf Of Choate, Paul@DDS Sent: Friday, October 03, 2008 4:10 PM To: SAS-L@LISTSERV.UGA.EDU Subject: Re: Puzzle: Converting 1-10 to 1,2,3,4,5,6,7,8,9,10 Yeah, the format only gets resolved before or after depending on double o...

Re: Puzzle: Converting 1-10 to 1,2,3,4,5,6,7,8,9,10 #4
Nice! But you assume string is a macro var. What about string is a data step var and the dataset has many records? On Fri, 3 Oct 2008 16:22:31 -0500, ./ ADD NAME=Data _null_, <iebupdte@GMAIL.COM> wrote: >All positive ranges? > >Thinking about a way to get SAS to do most of the work this is what I >came up with.... > >7227 %let string = 1-10,21,22,30-35,40,41; >7228 data _null_; >7229 length newstring $256; >7230 do _n_ = %qsysfunc(tranwrd(%superq(string),-,%str( to ))); >7231 newstring = catx(',',newstring,_n_); >7232 end; >7233 put 'NOTE: ' newstring=; >7234 run; > >NOTE: newstring=1,2,3,4,5,6,7,8,9,10,21,22,30,31,32,33,34,35,40,41 > > > >On 10/3/08, Paul Walker <walker.627@osu.edu> wrote: >> What is the best way to convert a string like 1-10 to a string like >> 1,2,3,4,5,6,7,8,9,10? The string is stored as a variable in a datastep. >> I am looking for a function that could be called like this maybe. >> >> data _null_; >> string = '1-10'; >> newstring = function(string); >> run; >> >> Add a twist to the puzzle: what if I mixed and matched. For example, a >> string 1-10,21,22,30-35,40,41. >> >> data _null_; >> string = '1-10,21,22,30-35,40,41'; >> newstring = function(string); >> run; >> >> newstring = 1,2,3,4,5,6,7,8,9,10,21,22,30...

Re: Puzzle: Converting 1-10 to 1,2,3,4,5,6,7,8,9,10 #6
All positive ranges? Thinking about a way to get SAS to do most of the work this is what I came up with.... 7227 %let string = 1-10,21,22,30-35,40,41; 7228 data _null_; 7229 length newstring $256; 7230 do _n_ = %qsysfunc(tranwrd(%superq(string),-,%str( to ))); 7231 newstring = catx(',',newstring,_n_); 7232 end; 7233 put 'NOTE: ' newstring=; 7234 run; NOTE: newstring=1,2,3,4,5,6,7,8,9,10,21,22,30,31,32,33,34,35,40,41 On 10/3/08, Paul Walker <walker.627@osu.edu> wrote: > What is the best way to convert a string like 1-10 to a string like > 1,2,3,4,5,6,7,8,9,10? The string is stored as a variable in a datastep. > I am looking for a function that could be called like this maybe. > > data _null_; > string = '1-10'; > newstring = function(string); > run; > > Add a twist to the puzzle: what if I mixed and matched. For example, a > string 1-10,21,22,30-35,40,41. > > data _null_; > string = '1-10,21,22,30-35,40,41'; > newstring = function(string); > run; > > newstring = 1,2,3,4,5,6,7,8,9,10,21,22,30,31,32,33,34,35,40,41 > > You get the idea. Any suggestions for the function? > > - Paul > ...

Re: Puzzle: Converting 1-10 to 1,2,3,4,5,6,7,8,9,10 #5
Wow! I didn't know that the do statement could do that! Certainly one = could write code to replace all dashes with a ' to '. =20 -Mary ----- Original Message -----=20 From: Miller, Scott=20 To: Mary ; walker.627@OSU.EDU=20 Sent: Friday, October 03, 2008 4:08 PM Subject: RE: Re: Puzzle: Converting 1-10 to 1,2,3,4,5,6,7,8,9,10 i did your approach, mary, except with a slight change in the numbers. = i replaced the - with ' to ' and used a do statement to get the values. = then used a similar sql statement to load those numbers into a macro = var. =20 data z; do x=3D1 to 10,21,22,30 to 35,40,41; output; end; run; Scott D. Miller, MA Evaluation and Informatics Analyst West Virginia Medical Institute (304) 346-9864 ext 2240 Every good scientist should be one part P.T. Barnum and one part B.F. = Skinner. Sumus quid sumus=20 ...and why did I leave the plow in the field, and look for a job in = the town -----Original Message----- From: SAS(r) Discussion [mailto:SAS-L@LISTSERV.UGA.EDU]On Behalf Of = Mary Sent: Friday, October 03, 2008 4:48 PM To: SAS-L@LISTSERV.UGA.EDU Subject: Re: Puzzle: Converting 1-10 to 1,2,3,4,5,6,7,8,9,10 I'm not sure I can actually do this, but I'll give an approach for = doing it; I think it could be done in a data step or in IML. Maybe = someone else can work out the code! =20 1. Take the original string and form a data set that creates an = observation for ...

Re: Puzzle: Converting 1-10 to 1,2,3,4,5,6,7,8,9,10 #2
I'm not sure I can actually do this, but I'll give an approach for doing = it; I think it could be done in a data step or in IML. Maybe someone = else can work out the code! =20 1. Take the original string and form a data set that creates an = observation for each value between the commas: 1-10,21,22,30-35,40,41 becomes 1-10 21 22 30-35 40 41 2. Take that new data set and search for a dash (using INDEX). If not = found, then output the value. If found, then assign the start value to = the part to the right of the dash, the ending value to the part to the = left of the dash, using SUBSTR. Convert the start and end value to = numeric, then do a do loop with an output, such as: do i=3Dstart to end; value=3Di; output; end; 3. Then you should wind up with values down of each of the individual = values: 1 2 3 ... 41 4. Then you can get the thing into a comma delimited string by a = couple of approaches. One is the Proc SQL into a variable list, such = as proc sql noprint; select value into :valuelist separated by ',' from values; quit; Or you could read the data set sequentially and then substring. =20 A similar approach could be used in IML- assign each value between the = commas to a matrix, then process each value in the matrix by searching = for the dash. If there's no dash, copy the value to the new matrix. = If there is a dash, then grab the start and end value and get into a do = loop and add each value as yo...

Re: Puzzle: Converting 1-10 to 1,2,3,4,5,6,7,8,9,10 #7
Hey Toby - What no regex? No hash? How about a proc format wrapped in a call execute? Data _Null_; Length NewString $ 200 ; String = '1-10,21,22,30-35,40,41' ; call execute ( "proc format; value numstr " || String || " ='Nums'; run ;"); Do _K = input(Scan( String , 1 , ',-' ),best12.) To input(Scan( String , -1 , ',-'),best12.); if put(_K,numstr.)='Nums' then NewString = CatX( ',' , NewString , _K ) ; End; Put NewString= ; run; Paul Choate DDS Data Extraction (916) 654-2160 -----Original Message----- From: SAS(r) Discussion [mailto:SAS-L@LISTSERV.UGA.EDU] On Behalf Of Toby Dunn Sent: Friday, October 03, 2008 1:55 PM To: SAS-L@LISTSERV.UGA.EDU Subject: Re: Puzzle: Converting 1-10 to 1,2,3,4,5,6,7,8,9,10 Data _Null_ ; Length NewString $ 200 ; String = '1-10,21,22,30-35,40,41' ; Do I = 1 To ( 1 + CountC( String , ',' ) ) ; TempA = Scan( String , I , ',' ) ; If Find( TempA , '-' ) Then Do ; Start = Input( Scan( TempA , 1 , '-' ) , Best12. ) ; Stop = Input( Scan( TempA , 2 , '-' ) , Best12. ) ; Do K = Start To Stop ; NewString = CatX( ',' , NewString , K ) ; End ; End ; Else Do ; NewString = CatX( ',' , NewString , TempA ) ; End ; End ; Put NewString= ; Run ; On Fri, 3 Oct 2008 16:27:44 -0400, Paul Walker <walker.627@OSU.EDU> wrot...

Re: Puzzle: Converting 1-10 to 1,2,3,4,5,6,7,8,9,10 #8
You program does not work "the first time" becasue NUMSTR does not exist. 7235 Data _Null_; 7236 Length NewString $ 200 ; 7237 String = '1-10,21,22,30-35,40,41' ; 7238 7239 7240 call execute ( "proc format; value numstr " || 7241 String || 7242 " ='Nums'; run ;"); 7243 7244 Do _K = input(Scan( String , 1 , ',-' ),best12.) To 7245 input(Scan( String , -1 , ',-'),best12.); 7246 if put(_K,numstr.)='Nums' then ------- 484 NOTE 484-185: Format NUMSTR was not found or could not be loaded. 7247 7248 NewString = CatX( ',' , NewString , _K ) ; 7249 End; 7250 7251 Put NewString= ; 7252 run; NewString= NOTE: CALL EXECUTE generated line. 1 + proc format; 1 + value numstr 1-10,21,22,30-35,40,41 ='Nums'; NOTE: Format NUMSTR has been output. 1 + run ; On 10/3/08, Choate, Paul@DDS <pchoate@dds.ca.gov> wrote: > Hey Toby - What no regex? No hash? > > How about a proc format wrapped in a call execute? > > Data _Null_; > Length NewString $ 200 ; > String = '1-10,21,22,30-35,40,41' ; > > call execute ( "proc format; value numstr " || > String || > " ='Nums'; run ;"); > > Do _K = input(Scan( String , 1 , &...

Re: Puzzle: Converting 1-10 to 1,2,3,4,5,6,7,8,9,10 #9
Yeah, the format only gets resolved before or after depending on double or single quotes. The datastep uses only whatever format is there when it executes....Oh well Paul Choate DDS Data Extraction (916) 654-2160 -----Original Message----- From: SAS(r) Discussion [mailto:SAS-L@LISTSERV.UGA.EDU] On Behalf Of ./ ADD NAME=Data _null_, Sent: Friday, October 03, 2008 4:00 PM To: SAS-L@LISTSERV.UGA.EDU Subject: Re: Puzzle: Converting 1-10 to 1,2,3,4,5,6,7,8,9,10 You program does not work "the first time" becasue NUMSTR does not exist. 7235 Data _Null_; 7236 Length NewString $ 200 ; 7237 String = '1-10,21,22,30-35,40,41' ; 7238 7239 7240 call execute ( "proc format; value numstr " || 7241 String || 7242 " ='Nums'; run ;"); 7243 7244 Do _K = input(Scan( String , 1 , ',-' ),best12.) To 7245 input(Scan( String , -1 , ',-'),best12.); 7246 if put(_K,numstr.)='Nums' then ------- 484 NOTE 484-185: Format NUMSTR was not found or could not be loaded. 7247 7248 NewString = CatX( ',' , NewString , _K ) ; 7249 End; 7250 7251 Put NewString= ; 7252 run; NewString= NOTE: CALL EXECUTE generated line. 1 + proc format; 1 + value numstr 1-10,21,22,30-35,40,41 ='Nums'; NOTE: Format NUMSTR has been output. 1 + run ; On ...

Re: Puzzle: Converting 1-10 to 1,2,3,4,5,6,7,8,9,10
Data _Null_ ; Length NewString $ 200 ; String = '1-10,21,22,30-35,40,41' ; Do I = 1 To ( 1 + CountC( String , ',' ) ) ; TempA = Scan( String , I , ',' ) ; If Find( TempA , '-' ) Then Do ; Start = Input( Scan( TempA , 1 , '-' ) , Best12. ) ; Stop = Input( Scan( TempA , 2 , '-' ) , Best12. ) ; Do K = Start To Stop ; NewString = CatX( ',' , NewString , K ) ; End ; End ; Else Do ; NewString = CatX( ',' , NewString , TempA ) ; End ; End ; Put NewString= ; Run ; On Fri, 3 Oct 2008 16:27:44 -0400, Paul Walker <walker.627@OSU.EDU> wrote: >What is the best way to convert a string like 1-10 to a string like >1,2,3,4,5,6,7,8,9,10? The string is stored as a variable in a datastep. >I am looking for a function that could be called like this maybe. > >data _null_; > string = '1-10'; > newstring = function(string); >run; > >Add a twist to the puzzle: what if I mixed and matched. For example, a >string 1-10,21,22,30-35,40,41. > >data _null_; > string = '1-10,21,22,30-35,40,41'; > newstring = function(string); >run; > >newstring = 1,2,3,4,5,6,7,8,9,10,21,22,30,31,32,33,34,35,40,41 > >You get the idea. Any suggestions for the function? > >- Paul ...

Puzzle: Converting 1-10 to 1,2,3,4,5,6,7,8,9,10
What is the best way to convert a string like 1-10 to a string like 1,2,3,4,5,6,7,8,9,10? The string is stored as a variable in a datastep. I am looking for a function that could be called like this maybe. data _null_; string = '1-10'; newstring = function(string); run; Add a twist to the puzzle: what if I mixed and matched. For example, a string 1-10,21,22,30-35,40,41. data _null_; string = '1-10,21,22,30-35,40,41'; newstring = function(string); run; newstring = 1,2,3,4,5,6,7,8,9,10,21,22,30,31,32,33,34,35,40,41 You get the idea. Any suggestions for the function? - Paul Just another possibility: %macro numlist(instring); %let j=1; %do %while(%scan(&instring,&j,',') ne ); %let instringPart=%scan(&instring,&j,','); %let start=%scan(&instringPart,1,'-'); %let stop =%scan(&instringPart,-1,'-'); %if &j=1 %then %let outstring=&start; %else %let outstring=&outstring%str(,)&start; %do i=%eval(&start+1) %to &stop; %let outstring=&outstring%str(,)&i; %end; %let j=%eval(&j+1); %end; %str(&outstring); %mend; %put %numlist(%str(1-10,21,22,30-35,40,41)); data _null_; length a $ 100; a="%numlist(%str(1-10,21,22,30-35,40,41))"; put a=; run; Think I've pushed the wrong button.... or this post will now show up twice... Just another possibility: %macro numlist(instring); %let j=1; ...

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[1 1 1 1 1 ;2 2 2 2 2 ;3 3 3 3 3 3;....;n n n n n]
Hi, Anybody knows how to create this matrix but without using any loops? a=[1 1 1 1 1 ;2 2 2 2 2 ;3 3 3 3 3 ;.......;n n n n n ] Thank you. Hana. Hana wrote: > Hi, > Anybody knows how to create this matrix but without using any loops? > a=[1 1 1 1 1 ;2 2 2 2 2 ;3 3 3 3 3 ;.......;n n n n n ] HELP REPMAT - Randy Hana wrote: > > > Hi, > Anybody knows how to create this matrix but without using any > loops? > a=[1 1 1 1 1 ;2 2 2 2 2 ;3 3 3 3 3 ;.......;n n n n n ] > > Thank you. > Hana. Hope this isn't homework. >> repmat([1:n]'...

Re: Subject: Building ACE 5.3.1 on Mac OS X (Tiger) 10.4.2 was [ace-users] Building ACE on Mac OSX 10.4
Hi Jason, Thanks for using the PRF. >> ACE VERSION: 5.3.1 This version of ACE is ANCIENT. The forthcoming ACE 5.4.8 beta should work "out of the box" for Mac OS X Tiger. If you want a preview, please download the version in our CVS repo at http://cvs.doc.wustl.edu/ take care, Doug >> HOST MACHINE and OPERATING SYSTEM: Mac OS X 10.4.2 >> COMPILER NAME AND VERSION (AND PATCHLEVEL): >> powerpc-apple-darwin8-gcc-4.0.1 >> >> CONTENTS OF $ACE_ROOT/ace/config.h: >> >> /* -*- C++ -*- */ >> // config-macosx.h,v 4.17 2003/01/20 20:02:12 seibel_r Exp >> >> // This configuration file is designed to work with the MacOS X operating >> system. >> >> #ifndef ACE_CONFIG_MACOSX_H >> #define ACE_CONFIG_MACOSX_H >> >> #if ! defined (__ACE_INLINE__) >> #define __ACE_INLINE__ >> #endif /* ! __ACE_INLINE__ */ >> >> #if defined (__GNUG__) >> # include "ace/config-g++-common.h" >> #endif /* __GNUG__ */ >> >> #undef ACE_HAS_EXPLICIT_TEMPLATE_INSTANTIATION >> >> #define ACE_SIZE_T_FORMAT_SPECIFIER ACE_LIB_TEXT ("%lu") >> >> #if defined (ACE_HAS_PENTIUM) >> # undef ACE_HAS_PENTIUM >> #endif /* ACE_HAS_PENTIUM */ >> >> #if !defined (_THREAD_SAFE) >> #define _THREAD_SAFE >&g...

RENEW 0.8.6.1.7.9.4.3.0.3.9.4.e164.arpa.
-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 ProvID: DENIC-24 Enum-Domain: 0.8.6.1.7.9.4.3.0.3.9.4.e164.arpa. Action: RENEW Enum-Holder: DENIC-24-KF108 Admin-C: DENIC-24-KF108 Tech-C: DENIC-24-TSB4 Zone-C: DENIC-24-TSB4 Nserver: ns.dnsnglab.ipv6.berkom.de. Nserver: ns2.dnsnglab.ipv6.berkom.de. Remarks: TSI ENUM-Trial Teilnehmer -----BEGIN PGP SIGNATURE----- Version: GnuPG v1.2.1 (GNU/Linux) iD8DBQFBRXqOS9pACF8jgjwRArEvAJ4jBAdqTC8AKL+c0LL4RgXZ7J1f5gCgwXVo FgJZgHLnEk64xIRCM+S5XuI= =dC1s -----END PGP SIGNATURE----- ...

Problem installing matplotlib 1.3.1 with Python 2.7.6 and 3.3.3 (release candidate 1)
Hello, I tried to install matplotlib 1.3.1 on the release candidates of Python 2.7.6 and 3.3.3. I am on Mac OS X 10.6.8. Although the installation gave no problems, there is a problem with Tcl/Tk. The new Pythons have their own embedded Tcl/Tk, but when installing matplotlib it links to the Frameworks version of Tcl and TK, not to the embedded version. This causes confusion when importing matplotlib.pyplot: objc[70648]: Class TKApplication is implemented in both /Library/Frameworks/Python.framework/Versions/2.7/lib/libtk8.5.dylib and /Library/Frameworks/Tk.framework/Versions/8.5/Tk. One of the two will be used. Which one is undefined. objc[70648]: Class TKMenu is implemented in both /Library/Frameworks/Python.framework/Versions/2.7/lib/libtk8.5.dylib and /Library/Frameworks/Tk.framework/Versions/8.5/Tk. One of the two will be used. Which one is undefined. objc[70648]: Class TKContentView is implemented in both /Library/Frameworks/Python.framework/Versions/2.7/lib/libtk8.5.dylib and /Library/Frameworks/Tk.framework/Versions/8.5/Tk. One of the two will be used. Which one is undefined. objc[70648]: Class TKWindow is implemented in both /Library/Frameworks/Python.framework/Versions/2.7/lib/libtk8.5.dylib and /Library/Frameworks/Tk.framework/Versions/8.5/Tk. One of the two will be used. Which one is undefined. And then later it gives a lot of error messages. So I think it should be linked to the embedded version. For this the matplotlib setupext.py should be ad...

Re: 7.3.3 behaving differently on OS X 10.2.6 and FreeBSD 4.8-STABLE
Culley, > But on my production machine postgresql complained about the order by > clause-- it wanted the table alias to be on last_name. I believe this is because you used "u.last_name" earlier in the statement, and the ORDER BY clause doesn't know that's what you mean. That's a guess that doesn't really explain why it'd work under one OS and not under another. Are the two versions of Postgres configured the same? -------------------------- David Olbersen iGuard Engineer St. Bernard Software > -----Original Message----- > From: ...

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