Greetings, I'm pretty sure that a Bezier curve can be represented exactly by a NURBS curve. However what I need is an algorithm to convert Bezier curves (Quadratic and Cubic) to a NURBS curve. If I'm not mistaken, it should involve manipulating the knots while using the same control points. I've seen an algorithm or two on the web but they seem to fail most of the time. Can you lead me in the right direction? Thanks, Abdo Haji-Ali Programmer In|Framez You simply take the Bezier control points plus additional degree-1 control points at the beginning and the end point of the curve, which are combined as multiple knots, like p0, p0, p0, p1, p2, p3, p3, p3 control points t0, t0, t0, t1, t2, t3, t3, t3 knotvector with t_(i+1) - t_i = const for a cubic Bezier curve. - NR Abdo Haji-Ali schrieb: > Greetings, > > I'm pretty sure that a Bezier curve can be represented exactly by a > NURBS curve. However what I need is an algorithm to convert Bezier > curves (Quadratic and Cubic) to a NURBS curve. If I'm not mistaken, it > should involve manipulating the knots while using the same control > points. I've seen an algorithm or two on the web but they seem to fail > most of the time. > Can you lead me in the right direction? > > Thanks, > Abdo Haji-Ali > Programmer > In|Framez > On Oct 12, 1:55 pm, News Reader <n...@nospam.edu> wrote: > You simply take the Bezier control points plus additional degree-1...

Hi there, In my application the user can bent bezier curves with 3 or 4 control points to almost any arbitrary shape. What I need to display to the user is the (approximated) radius of the largest circle, or rather circle arc, for which (at least a part of) the bezier curve is the tangent. This may sound a bit confusing, a small graphic may be helpful: www.barnholt.net/Bezier_to_radius.png A naive algorithm would start on either end of the bezier curve and work its way forward along the curve, using a circle with a certain max. radius and gradually decrease the circle radius until the bezier curve is tangent of part of the circle. But I'm sure, there's an intelligent way to solve the problem :-) Any ideas are welcome! regards, Jan Barnholt On 9 Oct 2005 00:20:26 -0700, "groups_account_barnholt_dot_net" <groups@barnholt.net> wrote: >What I need to display to the user is the (approximated) radius of the >largest circle, or rather circle arc, for which (at least a part of) >the bezier curve is the tangent. This may sound a bit confusing, a >small graphic may be helpful: >www.barnholt.net/Bezier_to_radius.png Your graphic does not fit your description, which makes it hard to be sure what you really want. At any point along a twice-differentiable curve there is a unique "osculating circle", which can be calculated from the curve and its derivatives at the point. In particular, the radius of the osculating circle is a close...

Hi All, I'm working on an evenlope distorion ala Adobe Illustrator. I was wondering: if the "envelope" is defined as 4 planar connected cubic bezier curves (i.e. the 12 control points on the boundary of a bezier patch), is there a way to obtain the other 4 control points making up a flat bezier patch so that the distortion is reduced to a simple quadrilateral into bezier-patch mapping? TIA Fernando Cacciola On Mon, 24 Nov 2003 22:07:24 -0300, "Fernando Cacciola" <fernando_cacciola@hotmail.com> wrote: >I'm working on an evenlope distorion ala Adobe Illustrator. >I was wondering: if the "envelope" is defined as 4 planar connected cubic >bezier curves (i.e. the 12 control points on the boundary of a bezier >patch), is there a way to obtain the other 4 control points making up a flat >bezier patch so that the distortion is reduced to a simple quadrilateral >into bezier-patch mapping? Sounds like you really want a Coons patch, named for Steven Coons. Call the corners bottom left, bottom right, top left, and top right. Parameterize each edge from 0 to 1, with u for left to right and v for bottom to top. Picking a value of u, we obtain a point on the bottom curve and a corresponding point on the top curve. Draw a straight line between them. Repeat for every value of u to give a "ruled surface". Do the same for v to get a second ruled surface. If we add the two together we repeat the effect of, say, the c...

Just like in topic. One possible approach is to employ appropriate numerical method for root finding, for example two-dimensional Newton iteration. There are other methods too, you may wish to check section 3.2 of "An Introducion to Ray Tracing" book or some of papers discussing this problem (starting from Kajiya's "Ray tracing parametric surfaces" from Siggraph '82). Alex. ...

Text on a curve Hi: Using the following Mathematica 6.0.1 code, I get a nice picture as follows: Module[{f, fs, t}, f[t_] = {Cos[t] + Sin[t], Sin[t]}; fs[t_] = D[f[t], t] // N; h = Graphics[Rotate[Style[Text[" T"], 14], 90 Degree]]; Show[Graphics[{Arrowheads[{{Automatic, Automatic, h}}], {Red, Arrow /@ MapThread[{#1 + 0.001 #2, (#1 - 2 #2)} &, {f /@ #, ({-1, 1} Reverse[#]/21) & /@ (#/ Sqrt[#.#] & /@ (fs /@ #))} &[#]]}, {Thickness[0.005], {Blue, Line[f /@ #]}}} &[ ...

I am just learning PSP7. I am trying to make a logo and I want to include text along a curved line. I am following tutorials on vatious topics but cannot find on bedning tect boxes. Any help? or point me to a site that explains this. Look for references to "Text on a path" "Lori" <spamme@mchsi.com> wrote in message news:ECoLb.2657$xy6.9604@attbi_s02... > I am just learning PSP7. I am trying to make a logo and I want to include > text along a curved line. I am following tutorials on vatious topics but > cannot find on bedning tect boxes. Any help? or ...

Part of the documentation for the latest version of FF has led me to <http://cubic-bezier.com/#.17,.67,.83,.67>, a marvelous page of graphic illustration what's a Bezier curve and how do "control points" control it. Of course, the PS curveto invocations all rely on Bezier curves, which is why I post this lovely find in the present NG. It's all graphics and no math, but I recommend it most highly anyway. Cheers, -- tlvp -- Avant de repondre, jeter la poubelle, SVP. ...

Im trying to write a bit of code that draws a bezier curve.... So far I have come up with..... please any suggestions what im doin wrong? Thanks. J int i; double t,delta; double [] oldx = new double[steps]; double [] oldy = new double[steps]; double [] newx = new double[steps]; double [] newy = new double[steps]; oldx[1] = xIn[0]; oldy[1] = yIn[0]; delta = 1.0/steps; for(i=1;i<=steps;i++) { t=i*delta; newx[i] = xIn[0] * (1.0-t) * (1.0-t) * (1.0-t) + xIn[1] * 3.0 * t * (1.0-t) * (1.0-t) + xIn[2] * 3.0 * t * t * (1.0-t) + xIn[3] * t * t * t; newy[i] = yIn[0] * (1.0-t) * (1.0-t) * (1.0-t) + yIn[1] * 3.0 * t * (1.0-t) * (1.0-t) + yIn[2] * 3.0 * t * t * (1.0-t) + yIn[3] * t * t * t; //draws cruve da.line(oldx[i],oldy[i],newx[i],newy[i]); //new values for next line oldx[i] = newx[i]; oldy[i] = newy[i]; } Done it, I used to many unnessary arrays. But it still draws over the point usin 10 sides, but perfectly when the number of sides is less than 10. Jen x public void drawBezier (int [] xIn, int [] yIn, int steps) { double t,delta, oldx, oldy, newx, newy; oldx = xIn[0]; oldy = yIn[0]; delta = 1.0/steps; for(t=delta;t<=1+delta;t+=delta) { newx = xIn[0] * (1.0-t) * (1.0-t) * (1.0-t) + xIn[1] * 3.0 * t * (1.0-t) * (1.0-t) + xIn[2] * 3.0 * t * t * (1.0-t) + xIn[3] * t * t * t; newy = yIn[0] * (1.0-t) * (1.0-t) * (1.0-t) + yIn[1] * 3.0 * t * (1.0-t) * (1.0-t) + yIn[2] * 3.0 * t * t * (1.0-t) + yI...

Hi, Just a brief question. In Autocad 2004, how do I align text around a (reference) curve ? I mean, each character should be rotated according to the curvature of a given entity, like an arc, for example. (I searched the online help but could find any references on this subject). Thank you, Fernando Ronci E-mail: fernandoronci@hotmail.com Google for "curvetext.zip" and you will find a LISP (arx) which does the job. Juergen "Fernando Ronci" <fernandoronci@hotmail.com> schrieb im Newsbeitrag news:d4e3407b.0409080502.64ce3285@posting.google.com... > Hi, > > Just a brief question. > In Autocad 2004, how do I align text around a (reference) curve ? May be of help... In ACAD2002 w/ Express Tools, there is Arc Aligned Text. On 9/8/2004 8:02 AM Fernando Ronci wrote: > Hi, > > Just a brief question. > In Autocad 2004, how do I align text around a (reference) curve ? > I mean, each character should be rotated according to the curvature of > a given entity, like an arc, for example. (I searched the online help > but could find any references on this subject). If you use ArcAlignedText in Express Tools as mentioned, consider that it may not be readable/editable if you send the drawing to someone without Express Tools. I don't know anything about the lisp mentioned, but there are lisp routines that calculate the position of each letter and use regular TEXT ...

How do I make text on a circle where the text is right-side-up above the circle and also on the lower side of the circle? I am inferring from the help files that the curve is directional and the text follows the direction? Everything I try, the text just follows around the curve and is upside down on the bottom. How can I make this work? Thanks, Jeff J. ----== Posted via Newsfeeds.Com - Unlimited-Unrestricted-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 120,000+ Newsgroups ----= East and West-Coast Server Farms - Total Privacy via Encryption =---...

Anyone know of a good plug-in for Photoshop that will allow the placing of text graphics onto a curve, or a circle? GB >Anyone know of a good plug-in for Photoshop that will allow the placing >of text graphics onto a curve, or a circle? The easiest way to do this is in a vector program like Adobe Illustrator; it takes less than five seconds. -- Rude T-shirts for a rude age: http://www.villaintees.com Art, literature, shareware, polyamory, kink, and more: http://www.xeromag.com/franklin.html Watch the end of this month when Photoshop 8.0 is announced. One new feature is supposed to...

What is "text + text" supposed to do right now? It doesn't seem very useful to me. What about making "text + text" as an equivalent for "text || text"? Most strongly-typed programming languages do this. And MS SQL Server too, I think (CMIIW). -- dave ---------------------------(end of broadcast)--------------------------- TIP 1: subscribe and unsubscribe commands go to majordomo@postgresql.org Am Freitag, 8. Oktober 2004 12:57 schrieb David Garamond: > What is "text + text" supposed to do right now? Nothing. > What about making "text + text" as an equivalent for "text > || text"? Most strongly-typed programming languages do this. And MS SQL > Server too, I think (CMIIW). What would this gain except for bloat? It's not like SQL is utterly compatible with any programming language; users will still have to learn all the operators anyway. -- Peter Eisentraut http://developer.postgresql.org/~petere/ ---------------------------(end of broadcast)--------------------------- TIP 9: the planner will ignore your desire to choose an index scan if your joining column's datatypes do not match Peter Eisentraut wrote: >>What is "text + text" supposed to do right now? > > Nothing. Then are these bugs? (7.4.5 and 8.0.0beta1 give same results). Frankly, the current behaviour is quite strange to me. ------------------ =...

How do I make text on a circle where the text is right-side-up above the circle and also on the lower side of the circle? I am inferring from the help files that the curve is directional and the text follows the direction? Everything I try, the text just follows around the curve and is upside down on the bottom. How can I make this work? Thanks, Jeff J. ----== Posted via Newsfeeds.Com - Unlimited-Unrestricted-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 120,000+ Newsgroups ----= East and West-Coast Server Farms - Total Privacy via Encryption =---...

I realize this has been discussed but..... aside from a sheet metal part (mike j wilson) can you put text in on a cylindrical surface as a string of text not individual letters? like you would in a molded part...made in usa, part number, date code, etc. the text needs to be truely cylindrical and with the ability to draft it for the mold etc. thanks. Depending on "how curved" it is you can use one of two methods: - offset from surface extrusion - new sw2004 "wrap" feature matt "3d" <jmiller@marvelindustries.com> wrote in news:qb6dnQLlso5TpZHd4p2dnA@...

Hi, I am newbie to bezier curves. I am trying to plot bezier curve on the screen. I am varying the parameter t from t=0.0 to t =1.0 (using standard bezier equation). Though I am incrementing t by equal amounts (ie. increment = 0.2), the distance between any two points on curve is not constant. Is there any way to achive this? I want the distance between any two consequtive points on the curve to remain constant. Thanks in advance, Best Regards, Yogesh Kini yogesh.kini@gmail.com wrote: > Though I am incrementing t by equal amounts (ie. increment = 0.2), > the distance between any two points on curve is not constant. Is > there any way to achive this? No simple way. Equidistant samples along a generic curve require a serious amount of calculus --- so much that it's often not worth doing. You have to compute the curve length integral and run a search on the result to find the point a given distance along the curve. For a bezier curve, that integral itself is quite challenging already, so it can only be done numerically. -- Hans-Bernhard Broeker (broeker@physik.rwth-aachen.de) Even if all the snow were burnt, ashes would remain. On 1 Sep 2005 03:05:01 -0700, yogesh.kini@gmail.com wrote: > I am newbie to bezier curves. I am trying to plot bezier curve on the >screen. I am varying the >parameter t from t=0.0 to t =1.0 (using standard bezier equation). > Though I am incrementing t by equal amounts (ie. increment = 0.2), the >distance bet...

I'm working to an algorithm to translate a dxf file to another format. This format have a primitive that rappresent the Bezier Curve for 4 points. DXF have instead n points for a BSpline curve. Can I consider the n points group of BSpline on sets of 4 points each other? ...

Anybody able to tell me how to draw a bezier curve with PSP8? The help system says something like, "you can draw bezier lines," but give NO info on how to do it. The option was right there in PSP7. TIA "Beacon TS" <richardsobocinski@comcast.net> wrote in news:D8OcncGxWJI30LSiXTWJhw@comcast.com: > Anybody able to tell me how to draw a bezier curve with PSP8? The > help system says something like, "you can draw bezier lines," but > give NO info on how to do it. The option was right there in PSP7. > TIA Try these--> http://moonsdesigns.co...

I am just learning PSP7. I am trying to make a logo and I want to include text along a curved line. I am following tutorials on vatious topics but cannot find on bedning tect boxes. Any help? or point me to a site that explains this. Look for references to "Text on a path" "Lori" <spamme@mchsi.com> wrote in message news:ECoLb.2657$xy6.9604@attbi_s02... > I am just learning PSP7. I am trying to make a logo and I want to include > text along a curved line. I am following tutorials on vatious topics but > cannot find on bedning tect boxes. Any help? or ...

Anybody able to tell me how to draw a bezier curve with PSP8? The help system says something like, "you can draw bezier lines," but give NO info on how to do it. The option was right there in PSP7. TIA "Beacon TS" <richardsobocinski@comcast.net> wrote in news:D8OcncGxWJI30LSiXTWJhw@comcast.com: > Anybody able to tell me how to draw a bezier curve with PSP8? The > help system says something like, "you can draw bezier lines," but > give NO info on how to do it. The option was right there in PSP7. > TIA Try these--> http://moonsdesigns.co...

Wondering how what I input to my UTF-8 terminal gets passed along through my patched [1] trn ... Cyrillic: А Б В Г Д Е Ж З И Й К Л М Н О П а б в г д е ж з и й к л м н о п IPA: ᴀ ᴁ ᴂ ᴃ ᴄ ᴅ ᴆ ᴇ ᴈ ᴉ ᴊ ᴋ ᴌ ᴍ ᴎ ᴏ ɀ Ɂ ɂ Ƀ Ʉ Ʌ Ɇ ɇ Ɉ ɉ Ɋ ɋ Ɍ ɍ Ɏ ɏ [1] https://groups.google.com/d/msg/comp.sys.raspberry-pi/7Z37Hdrm0DM/6aqD-reXFzAJ ...

Hi, I'm not a mathematician so I guess my problem has a very simple solution. In general I'm trying to find a way to bezier curve fit my signals. I found that the polyfit fuctions does a good job, but I don't know how to convert the polynomial coefficients to the bezeir control points. I find it difficult to understand the Bezier-Bernstein formula. can anyone please help me? thanks, zachi Hi Zachi; I have wrote some time ago two functions; the first, Bernstein.m, computes the Bernestein polynomials on n+1 assigned points, and the second, Bezier3d.m, the relative ...

In a post in 2004 (hurray for archives), Dave Eberly explained why you can't have a polynomial offset curve be itself a polynomial. His post read: "Generally, y, if you start with a polynomial curve and try to offset, the result will no longer be a polynomial curve. The idea is as follows for a planar curve. "Let et the planar curve be parameterized as P(t). A unit-length tangent vector is T(t) = P'(t)/|P'(t)| where P'(t) is the derivative of P (t) and |P'(t)| is the length of the derivative. In the plane, you can write T(t) = (cos(A(t)),sin(A(t))) for some angle A(t). A unit- length normal is N(t) = (-sin(A(t)),cos(A(t))) and is oriented to point to the "left" of the curve as you traverse it in the tangential direction. "Let et Q(t) be a curve that is to be "offset" from P(t) by a constant distance r. The offset is presumed to be in the normal direction, so you want Q(t) = P(t) + r*N(t). If P(t) is a polynomial curve, the only way for Q(t) to be a polynomial curve is if N(t) has polynomial components. Now notice that the components of N(t) are the components of T(t), and the components of T(t) are polynomial terms [P'(t) has polynomial components] *divided* by the length of P'(t), a term that is not generally a polynomial. When the length is not a polynomial, neither is Q(t)." Reading this seems to imlpy that the offset can be polynomial in those cases where |P'(t)| is polynom...

I am using keyval to set a "scaled" parameter and am having trouble getting the right behavior, which is: If I \usepackage{package} with no [scaled] option, I want to set a variable to a compile-time-specified default, say "s*[a.b]". If I \usepackage[scaled]{package}, same thing. And if I \usepackage[scaled=x.y], I want to set the variable to "s*[x.y]". (This is for font scaling, and I've used as my model the Helvetica scaled parameter.) The variable name (for the purposes of this conversation) is pnm@scaled. What I have that's not working correctly is: \expandafter\ifx\csname pmn@scaled\endcsname\relax \let\pmn@scaled\@empty \else \edef\pmn@scaled{s*[1.2]}% \fi I think what this says is "if pnm@scaled is not defined (case 1), leave it empty, otherwise set it to "s[1.2]". But the else clause is not working correctly, and I don't know how to differentiate between "defined by keyval but with no value" and "defined by keyval but with a value". Also I'm pretty sure I don't really know the difference between \let and \edef. Any help gratefully appreciated. Thanks. JDO john_owens@yahoo.com schrieb: > I am using keyval to set a "scaled" parameter and am having trouble > getting the right behavior, which is: > > If I \usepackage{package} with no [scaled] option, I want to set a > variable to a compile-time-specified default, say "s*[a.b]". > ...

Hi all, If I have a Bezier curve (of any order), I know how to clip at a 't' value using de Casteljau's algorithm, and I know how to compute the arc length of the curve without flattening, using the Gauss-Legendre quadrature approach for computing the curve's integral over interval t=[0,1]. So far so good - the real problem is this: how do I determine which 't' value corresponds to a certain distance along the curve? Let's say I have a curve with a computed arc length over interval [0,1] of 100 units. In order to travel across this curve at some (arbitrary) fixed-distance interval I will need to know which 't' values the distances map to, but if I need the 't' value for a distance of 71 units along the curve, 0.71 is the least likely value it will have =) Which function, or set of functions, can be used to determine the 't' value based on arc length? Regards, - Mike "Pomax" Kamermans nihongoresources.com On 23.04.2011 20:26, Pomax wrote: > the real problem is this: how do I determine which 't' value corresponds to a > certain distance along the curve? The same old way you solve any problem involving how to find the inverse of a function that doesn't allow itself to be inverted analytically: use a numerical root finder to find the place where the function takes on the given value, i.e. solve length(Curve, t) = l > Which function, or set of functions, can be used to determine the &#...

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