HPUX, aCC (HP ANSI C++ B3910B A.03.27)
I have to determine the path of an executable. I want the same value
as argv[0]. The problem is - my code is a library. I cannot use
argv[0]. I want to use my code in a shared library and (statically
linked) in an executable. Is there a way to determine this path?
Thanks
T.M.
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Torsten
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6/14/2005 12:37:57 PM |
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Torsten Mueller <dev-null@shared-files.de> writes:
> HPUX, aCC (HP ANSI C++ B3910B A.03.27)
>
> I have to determine the path of an executable. I want the same value
> as argv[0]. The problem is - my code is a library. I cannot use
> argv[0]. I want to use my code in a shared library and (statically
> linked) in an executable. Is there a way to determine this path?
In general, no. Why do you need this information?
--
M�ns Rullg�rd
mru@inprovide.com
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iso
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6/14/2005 1:06:35 PM
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Torsten Mueller wrote:
> HPUX, aCC (HP ANSI C++ B3910B A.03.27)
>
> I have to determine the path of an executable.
Why? In my experience, when someone says that they have to determine the
path of an executable, they are trying to solve the wrong problem.
Perhaps we can help you solve the right problem.
> I want the same value
> as argv[0].
Which isn't guaranteed to be a path, let alone "the path to the executable".
> The problem is - my code is a library. I cannot use
> argv[0].
And you wouldn't want to, even if you could.
>I want to use my code in a shared library and (statically
> linked) in an executable. Is there a way to determine this path?
Short answer: No, there is no way to determine the path to the executable.
Long answer: Yes, there are several, implementation specific, ways to do
this, but none are guaranteed to be accurate or correct during the
execution lifetime of the process.
- --
Lew Pitcher, IT Specialist, Enterprise Data Systems
Enterprise Technology Solutions, TD Bank Financial Group
(Opinions expressed here are my own, not my employer's)
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Lew
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6/14/2005 1:07:15 PM
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Lew Pitcher <Lew.Pitcher@td.com> schrieb:
> > I have to determine the path of an executable.
>
> Why?
(This question seems to be always the first question ...)
> In my experience, when someone says that they have to determine the
> path of an executable, they are trying to solve the wrong problem.
> Perhaps we can help you solve the right problem.
Yeah, it's just to implement the same algorithm that is used under
Windows. I port a software component and it has a config file located
near the executable.
By the while I read somewhere UNIX programmers should use just a fixed
path for config files of an application, /var/opt/PACKAGE or
/usr/local/etc or something like this. I can do this and this would
indeed be a simple solution for the problem. But it's different than
under Windows and then I have to manage such differences. Other people
must know them to avoid confusion.
OK, thanks.
T.M.
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Torsten
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6/14/2005 2:37:36 PM
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Torsten Mueller <dev-null@shared-files.de> writes:
> Lew Pitcher <Lew.Pitcher@td.com> schrieb:
>
>> > I have to determine the path of an executable.
>>
>> Why?
>
> (This question seems to be always the first question ...)
>
>> In my experience, when someone says that they have to determine the
>> path of an executable, they are trying to solve the wrong problem.
>> Perhaps we can help you solve the right problem.
>
> Yeah, it's just to implement the same algorithm that is used under
> Windows. I port a software component and it has a config file located
> near the executable.
Right, that is the wrong problem.
On unix, there may be several users running the same program, and they
won't have all the access rights to read/write the configuration file.
So you should put configuration files in the current user home
directory (or if it's a system-wide tool like a server daemon, in /etc).
#define PNAME "MyProgram"
char* conf_path=concatenate(getenv("HOME"),"/.",PNAME,".conf",0);
If you will you can either have a #include directive in
~/.MyProgram.conf that would allow each user to include at will a
common configuration file (eg. /etc/MyProgram.defaults), or you can
process the two files:
#define PREFIX "" /* could be "/usr/local" */
#define PNAME "MyProgram"
char* global_conf_path=concatenate(PREFIX,"/etc/",PNAME,".conf",0);
char* user_conf_path=concatenate(getenv("HOME"),"/.",PNAME,".conf",0);
> By the while I read somewhere UNIX programmers should use just a fixed
> path for config files of an application, /var/opt/PACKAGE or
> /usr/local/etc or something like this. I can do this and this would
> indeed be a simple solution for the problem. But it's different than
> under Windows and then I have to manage such differences. Other people
> must know them to avoid confusion.
Windows users are rarely unix users, so it won't confuse them to put
configuration files in /etc or in $HOME. On the other hand, it would
confuse unix administrators and unix user a lot if you did not put
them in /etc or in $HOME.
--
__Pascal Bourguignon__ http://www.informatimago.com/
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Pascal
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6/14/2005 3:38:32 PM
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Pascal Bourguignon wrote:
> Torsten Mueller <dev-null@shared-files.de> writes:
>
>
>>Lew Pitcher <Lew.Pitcher@td.com> schrieb:
>>
>>
>>>>I have to determine the path of an executable.
>>>
>>>Why?
>>
>>(This question seems to be always the first question ...)
>>
>>
>>>In my experience, when someone says that they have to determine the
>>>path of an executable, they are trying to solve the wrong problem.
>>>Perhaps we can help you solve the right problem.
>>
>>Yeah, it's just to implement the same algorithm that is used under
>>Windows. I port a software component and it has a config file located
>>near the executable.
>
>
> Right, that is the wrong problem.
>
> On unix, there may be several users running the same program, and they
> won't have all the access rights to read/write the configuration file.
> So you should put configuration files in the current user home
> directory (or if it's a system-wide tool like a server daemon, in /etc).
To expand on that point a bit,
Per-user configuration should be stored in a file or directory in the
user's home directory
Systemwide configuration and/or configuration defaults, should be stored
in a file or directory in one of the standard configuration directories.
A user-invoked program should use the config file in the home directory,
and perhaps fill in the unspecified values from the system config file.
This might be implemented as
load system config file
load user config file, overriding values of system config file
or it might be implemented as
load user config file
load system config file, discarding values already set by user config
or, it might even be implemented as
if user config exists
load user config file
else
load system config file
fi
- --
Lew Pitcher, IT Specialist, Enterprise Data Systems
Enterprise Technology Solutions, TD Bank Financial Group
(Opinions expressed here are my own, not my employer's)
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Lew
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6/14/2005 4:19:20 PM
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>I have to determine the path of an executable. I want the same value
>as argv[0].
You do know that the value of argv[0] can have absolutely NOTHING
to do with the path to an executable, right? And if there's any
advantage to be gained by making your program find the WRONG
executable, someone WILL invoke it that way maliciously.
>The problem is - my code is a library. I cannot use
>argv[0]. I want to use my code in a shared library and (statically
>linked) in an executable. Is there a way to determine this path?
What were you planning on using this value for? Nothing besides
error messages, I hope. It doesn't sound very secure.
Gordon L. Burditt
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gordon
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6/14/2005 4:26:17 PM
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Gordon Burditt wrote:
>>I have to determine the path of an executable. I want the same value
>>as argv[0].
>
>
> You do know that the value of argv[0] can have absolutely NOTHING
> to do with the path to an executable, right?
Perhaps a demonstration for the OP would be in order....
First, a program that echos all it's arguments, including argv[0]
pitchl@srdscs05:~/code/argv0$ cat showargs.c
#include <stdio.h>
#include <stdlib.h>
int main(int argc, char *argv[])
{
int count;
printf("%s Begins\n",__FILE__);
printf("argc == %d\n",argc);
for (count = 0; count < argc; ++count)
printf("argv[%d] == \"%s\"\n",count,argv[count]);
printf("%s Ends\n",__FILE__);
return EXIT_SUCCESS;
}
pitchl@srdscs05:~/code/argv0$ cc -o showargs showargs.c
pitchl@srdscs05:~/code/argv0$ showargs one two 3
showargs.c Begins
argc == 4
argv[0] == "showargs"
argv[1] == "one"
argv[2] == "two"
argv[3] == "3"
showargs.c Ends
As you see, showargs echo's all it's arguments, including argv[0]
Now, let's use exec(3) to run showargs for us.
pitchl@srdscs05:~/code/argv0$ cat arg0.c
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
int main(void)
{
execl("./showargs",
"*&&%##/##@$@@\\... this is not my path at all :-( ",
"an argument",
NULL);
return EXIT_FAILURE;
}
pitchl@srdscs05:~/code/argv0$ cc -o arg0 arg0.c
pitchl@srdscs05:~/code/argv0$ arg0
showargs.c Begins
argc == 2
argv[0] == "*&&%##/##@$@@\... this is not my path at all :-( "
argv[1] == "an argument"
showargs.c Ends
As you can see, showargs ran, but argv[0] /was not/ the path to the
executable. In fact, argv[0] isn't a path to anything at all. And, this
is perfectly legal in a Unix system.
Now, lets try a variation. No argv[0] at all...
pitchl@srdscs05:~/code/argv0$ cat noargs.c
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
int main(void)
{
execl("./showargs",
NULL);
return EXIT_FAILURE;
}
pitchl@srdscs05:~/code/argv0$ cc -o noargs noargs.c
pitchl@srdscs05:~/code/argv0$ noargs
showargs.c Begins
argc == 0
showargs.c Ends
pitchl@srdscs05:~/code/argv0$
Here, showargs ran, but it didn't even get garbage as argv[0]. Instead,
it got nothing at all, no arg[0] whatsoever. Again, perfectly legal in
Unix, but bad breakage for a program that thinks that MSWindows rules apply.
- --
Lew Pitcher, IT Specialist, Enterprise Data Systems
Enterprise Technology Solutions, TD Bank Financial Group
(Opinions expressed here are my own, not my employer's)
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Lew
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6/14/2005 4:41:17 PM
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"Torsten Mueller" <dev-null@shared-files.de> wrote in message
news:uoea9vwb2.fsf@fastmail.fm...
> Lew Pitcher <Lew.Pitcher@td.com> schrieb:
>
>> > I have to determine the path of an executable.
>>
>> Why?
>
> (This question seems to be always the first question ...)
>
>> In my experience, when someone says that they have to determine the
>> path of an executable, they are trying to solve the wrong problem.
>> Perhaps we can help you solve the right problem.
>
> Yeah, it's just to implement the same algorithm that is used under
> Windows. I port a software component and it has a config file located
> near the executable.
>
> By the while I read somewhere UNIX programmers should use just a fixed
> path for config files of an application, /var/opt/PACKAGE or
> /usr/local/etc or something like this. I can do this and this would
> indeed be a simple solution for the problem. But it's different than
> under Windows and then I have to manage such differences. Other people
> must know them to avoid confusion.
>
> OK, thanks.
>
> T.M.
Encapsulate the differences. I have "ConfigSettings" library code that
supports global and local settings. Local setting are per user. On Windows
the code uses the registry and uses current user for local and current
machine for global. On Unix systems the settings are saved in text files.
Local settings are in a hidden directory in the users home directory and
global settings are in /opt. The config settings take a company name as a
parameter. On Windows this is the registry directory and on unix a file
directory. For example the Unix global setting directory would be
/opt/Saperion. The Unix local directory would be $HOME/.Saperion/.
Norman
Saperion Inc.
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Norman
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6/14/2005 5:44:26 PM
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TJB replied to:
> In general, no. Why do you need this information?
I'm -shocked- that this answer is no.
In Windows land you would use this to figure where your installation
directory is. At start up I do something like this:
void layout_window_type::cd_to_self()
{
wchar_t buffer[ 16384 ];
GetModuleFileName( NULL, buffer, DIM(buffer) );
wchar_t *last_slash, *p;
last_slash = buffer;
p = buffer;
while (*p) {
p++;
if (*p == '\\') {
last_slash = p;
}
}
if (*last_slash == '\\') {
*last_slash = 0;
SetCurrentDirectory( buffer );
}
}
Then, I can hang configuration information off of the application's
directory So, regardless of the current directory of an application,
it can find its own root directory. Then, you can have configuration
stuff inside of that directory, and you don't need the registry any
more.
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stork
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6/14/2005 10:58:08 PM
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On Tue, 14 Jun 2005, stork wrote:
> I'm -shocked- that this answer is no.
Welcopme to proper programming!
> In Windows land you would use this to figure where your installation
> directory is. At start up I do something like this:
UNIX is not Windoze (thankfully).
> Then, I can hang configuration information off of the application's
> directory So, regardless of the current directory of an application,
> it can find its own root directory. Then, you can have configuration
> stuff inside of that directory, and you don't need the registry any
> more.
UNIX doesn't have a registry. And its designed to be multiuser from
the outset.
--
Rich Teer, SCNA, SCSA, OpenSolaris CAB member
President,
Rite Online Inc.
Voice: +1 (250) 979-1638
URL: http://www.rite-group.com/rich
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Rich
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6/14/2005 11:15:09 PM
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Lew Pitcher <Lew.Pitcher@td.com> schrieb:
> argv[0] == "showargs"
> argv[0] == "*&&%##/##@$@@\... this is not my path at all :-( "
Sure. I know this. It depends on several conditions and on the OS
itself. In Windows it's always the same value containing an absolute
path.
T.M.
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Torsten
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6/15/2005 5:18:34 AM
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Torsten Mueller <dev-null@shared-files.de> writes:
> Lew Pitcher <Lew.Pitcher@td.com> schrieb:
>
>> argv[0] == "showargs"
>> argv[0] == "*&&%##/##@$@@\... this is not my path at all :-( "
>
> Sure. I know this. It depends on several conditions and on the OS
> itself.
It has nothing to do with OS. The OS just passes on whatever value
was given to the exec() call.
> In Windows it's always the same value containing an absolute path.
So let it be that way in Windows. Whatever OS you're writing for, you
have to play by the rules it sets. One of the rules in Unix is that
argv[0] can be anything or nothing.
--
M�ns Rullg�rd
mru@inprovide.com
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iso
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6/15/2005 8:19:34 AM
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Torsten Mueller wrote:
> Lew Pitcher <Lew.Pitcher@td.com> schrieb:
>
>
>> argv[0] == "showargs"
>> argv[0] == "*&&%##/##@$@@\... this is not my path at all :-( "
>
>
> Sure. I know this. It depends on several conditions and on the OS
> itself. In Windows it's always the same value containing an absolute
> path.
P'haps an analogy will help.
I live in Canada, where we drive on the right side of the road.
I want to move to Britain, where they drive on the left side of the
road. However, I /insist/ that I always be permitted to drive on the
right side of the road in Britain, because the side of the road that
traffic drives on depends on several conditions, and in Canada, those
conditions lead to driving on the right side. Since I can do it in
Canada, I should be able to do it in Britain.
Now, tell me what the consequences of my decision (and my disregard for
the traffic laws of Britain) will be.
By analogy, something that works in Windows is not guaranteed to work
/anywhere else/. And, when you are using Unix, you are using Unix, not
Microsoft Windows. Different rules of the road apply, and you have to
change your plans accordingly.
My little demo just shows that there /are/ different road rules between
Unix and Windows, and /why/ you should be mindfull of them.
- --
Lew Pitcher, IT Specialist, Enterprise Data Systems
Enterprise Technology Solutions, TD Bank Financial Group
(Opinions expressed here are my own, not my employer's)
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Lew
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6/15/2005 12:52:30 PM
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Lew Pitcher <Lew.Pitcher@td.com> schrieb:
> I live in Canada, where we drive on the right side of the road.
>
> I want to move to Britain, where they drive on the left side of the
s/left/wrong/ ;-)
> By analogy, something that works in Windows is not guaranteed to work
> /anywhere else/. And, when you are using Unix, you are using Unix, not
Most of the time, something that works in Windows is even guaranteed
not to work anywhere else.
Markus
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Markus
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6/15/2005 2:01:00 PM
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"stork" <tbandrow@mightyware.com> writes:
> TJB replied to:
>
>> In general, no. Why do you need this information?
>
> I'm -shocked- that this answer is no.
>
> In Windows land you would use this to figure where your installation
> directory is. At start up I do something like this:
[...{blah blah blah ... more windows code}...] ;-)
If you need to locate the installation directory, you can easily do it
in unix:
----(install-script)----------------------------------------------------
#!/bin/bash
# installation script
TARBALL="$1"
installdir="$2"
[ -z "$installdir" ] && read -p 'Where do you want to install?' installdir
mkdir -p "$installdir"
tar -C "$installdir" -zxf "$TARBALL"
sed -e "s/installdir/$installdir/g" > "$installdir/pgm" <<EOF
#!/bin/bash
export RESOURCES="installdir"
exec "$RESOURCES/bin/pgm" "$@"
EOF
chmod 755 "$installdir/pgm"
------------------------------------------------------------------------
Now, you install your program pgm with:
./install-script pgm.tar.gz /opt/pgm
and instead of launching the program with: /opt/pgm/bin/pgm, you
launch it with /opt/pgm/pgm
Since most probably you'll have other installation specific stuff to
do, configure and pass to the program, these trampoline scripts are
quite useful.
--
__Pascal Bourguignon__ http://www.informatimago.com/
There is no worse tyranny than to force a man to pay for what he does not
want merely because you think it would be good for him. -- Robert Heinlein
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Pascal
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6/15/2005 7:45:19 PM
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It seems to me that the success of Unix rests mightily on how directory
structures are used and enforced. If you take any Linux or Solaris
installation, the directory tree is absolutely beautiful compared to
the wretched mess that is Win32. But, as someone who flirts with Unix
but has yet to seal the deal, that beautiful tree is daunting in that I
have no global way of understanding what all of those conventions are.
Is there somewhere out there a global map of Unix that just explains
what each of the directories is for and how the structure is organized?
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stork
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6/16/2005 4:20:14 PM
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On Thu, 16 Jun 2005, stork wrote:
> It seems to me that the success of Unix rests mightily on how directory
> structures are used and enforced. If you take any Linux or Solaris
> installation, the directory tree is absolutely beautiful compared to
> the wretched mess that is Win32. But, as someone who flirts with Unix
> but has yet to seal the deal, that beautiful tree is daunting in that I
> have no global way of understanding what all of those conventions are.
> Is there somewhere out there a global map of Unix that just explains
> what each of the directories is for and how the structure is organized?
On Solaris, type man filesystem .
HTH,
--
Rich Teer, SCNA, SCSA, OpenSolaris CAB member
President,
Rite Online Inc.
Voice: +1 (250) 979-1638
URL: http://www.rite-group.com/rich
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Rich
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6/16/2005 7:17:41 PM
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Rich Teer wrote:
> On Thu, 16 Jun 2005, stork wrote:
>
>
>>It seems to me that the success of Unix rests mightily on how directory
>>structures are used and enforced. If you take any Linux or Solaris
>>installation, the directory tree is absolutely beautiful compared to
>>the wretched mess that is Win32. But, as someone who flirts with Unix
>>but has yet to seal the deal, that beautiful tree is daunting in that I
>>have no global way of understanding what all of those conventions are.
>>Is there somewhere out there a global map of Unix that just explains
>>what each of the directories is for and how the structure is organized?
>
>
> On Solaris, type man filesystem .
On Linux, type "man hier"
And, of course, read the "Linux Filesystem Hierarchy Standard"
http://www.pathname.com/fhs/
- --
Lew Pitcher
Master Codewright & JOAT-in-training | GPG public key available on request
Registered Linux User #112576 (http://counter.li.org/)
Slackware - Because I know what I'm doing.
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Lew
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6/17/2005 1:06:15 AM
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