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What does 224.0.0.0 do?

Why is there a 224.0.0.0 in all systems and why do I need it?



seems to me it wastes good system overhead.



Carl

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Carl6360 (38)
5/10/2006 4:13:14 PM
comp.unix.sco.misc 3925 articles. 0 followers. Post Follow

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#if 0?0?0:0:0
The following 4-lines source fragment test.c (fourth line empty) #if 0?0?0:0:0 #endif int main(void){return 0?0?0:0:0;} cause: test.c(1) : fatal error C1017: invalid integer constant expression when compiled by cl.exe aka "Microsoft (R) 32-bit C/C++ Optimizing Compiler Version 15.00.30729.01 for 80x86". On the other hand this compile and runs fine. #if 0?(0?0:0):0 #endif int main(void){return 0?0?0:0:0;} Did I hit a but it this compiler's preprocessor? Francois Grieu On 3/30/2010 12:47 PM, Francois Grieu wrote: > The following 4-lines source fr...

(= 0/0 0/0)
Hi, shouldn't > (= 0/0 0/0) => NIL or > (= 0/0 0/0) => T instead of giving out division by zero? 0/0 is different from 1/0, which is the non-existent number n such that 1 x n = 0. The actual result of that expression depends of what you think 0/0 is. I personally feel that 0/0 is any number n such that 0 x n = 0, that is all numbers. hal9@cyberspace.org (Hal Niner) writes: > Hi, > > shouldn't > > > (= 0/0 0/0) => NIL > > or > > > (= 0/0 0/0) => T > > instead of giving out division by zero? 0/0 is different fro...

IP 0.0.0.0/0
Hi Any useful link that explains this IP address range in details, please? Thanks in advance! The Dude In article <Jp6Hg.458762$IK3.24918@pd7tw1no>, The Dude <The Dude@thedu.de> wrote: >Any useful link that explains this IP address range in details, please? Urrr -- 0.0.0.0/0 is the *entire* IPv4 address range, and 0.0.0.0/32 is just the single IPv4 address 0.0.0.0. For any given network, the lowest address in the network is reserved. Historically, the lowest address was one of the two allowed choices for the broadcast address; later, the broadcast a...

0.0**0 = ?
I'm wondering if 0.0**0 (as opposed to 0.0**0.0) has the value 1 as per fortran standard or if this is left to the compiler vendors (different vendors do different things, unhappily). Thanks, Joost Joost VandeVondele wrote: > I'm wondering if 0.0**0 (as opposed to 0.0**0.0) has the value 1 as > per fortran standard or if this is left to the compiler vendors > (different vendors do different things, unhappily). > > Thanks, > > Joost Surely, 0.0**0.0 is mathematically undefined? Therefore, I wouldn't expect the standard to make any pronouncement about the ...

what does the 224.0.0.0 do?
there is always a 224.0.0.0 route in all systems. what does it do and why do I need to have it? Carl Carl wrote: > there is always a 224.0.0.0 route in all systems. what does it do > and why do I need to have it? > http://en.wikipedia.org/wiki/IP_Multicast ...

"some\0\0\0\0\0\0"
can i use such form of adding zeros to the strings/literals to 'pad' them with zeros ? or this is not guwranteed to work? need that for assuring that strings for example arepadded to some amount of bytes thus using fast compare which only checks some amount of data and do not bother for checking ends, etc 9you know what i mean) On Thu, 13 Aug 2015 12:30:19 -0700, fir saw fit to publish the following: > can i use such form of adding zeros to the strings/literals to 'pad' > them with zeros ? Yes you can. (I feel SOOO presidential right now) > or this is n...

0:0:0:0:phone
Under kerio Admin screen,local Address I get: 0:0:0:0:phone where "phone" is the local port number. What the hell is that supposed to mean? MikeStevens.invalid@spamtrap.org wrote: > Under kerio Admin screen,local Address I get: 0:0:0:0:phone > > where "phone" is the local port number. What the hell is that supposed to > mean? That's illegal -- there should be nothing coming from 0.0.0.0 at all, on ANY port. Block that IP outright. -- Cinemuck, n.: The combination of popcorn, soda, and melted chocolate which covers the floors of movie theaters. -- Rich Hall, "Sniglets" 0.0.0.0 is seen as YOUR ip address until you get assigned a ip address. They even said it was their local port, so its something just listening on a local port which has the alias 'phone'. "NeoSadist" <neosad1st@charter.net> wrote in message news:vvscmg52kap0fc@corp.supernews.com... MikeStevens.invalid@spamtrap.org wrote: > Under kerio Admin screen,local Address I get: 0:0:0:0:phone > > where "phone" is the local port number. What the hell is that supposed to > mean? That's illegal -- there should be nothing coming from 0.0.0.0 at all, on ANY port. Block that IP outright. -- Cinemuck, n.: The combination of popcorn, soda, and melted chocolate which covers the floors of movie theaters. -- Rich Hall, "Sniglets" Go into the Firewall Status...

what is the significance of 0.0.0.0
is this the default gateway of whole internet. or is this the default gateway of a whole class A ip addresses. or is this a network address of a particular sub-net. please explain it pragmatically with regards novice wrote: > is this the default gateway of whole internet. > or is this the default gateway of a whole class A ip addresses. > > or is this a network address of a particular sub-net. > please explain it pragmatically > with regards Written that way, it's nothing more than an IP address. On 10/04/2010 02:53 PM, novice wrote: > is this the default gateway of whole internet. > or is this the default gateway of a whole class A ip addresses. > > or is this a network address of a particular sub-net. > please explain it pragmatically > with regards It's an invalid IP address. What 0.0.0.0 actually MEANS depends on the program you're using it with. -- Linards Ticmanis On Oct 4, 8:53=A0am, novice <rajat123si...@gmail.com> wrote: > is this the default gateway of whole internet. > or is this the default gateway of a whole class A ip addresses. > > or is this a network address of a particular sub-net. > please explain it pragmatically > with regards Depending on where you got the 0.0.0.0 from, it can have different meanings. In a socket(7) call, it generally means "all addresses", as in "bind to all addresses on this system" (bind(2)) In netstat(8), it generally means &qu...

How to interpolate a [0 0 0 1 0 0 ...0 1 0 0 0 ...0 0] vector please help
dear friends, i have t vector; t=linspace(0,.00007,76); k vector is [0 0 0 1......1 0 0 ..], its like all zeros except two 1`s, on a different time instants. when i apply this command ; k=interp1(tau,k,t); tau is also the same as t. one question is that,do we need to interpolate the vector k from one time vector to another of the same length? as here length(t)=length(tau). second question is that when i apply this command, the vector k is returned as a single entry???? please help me on this one. thanks "salman " <salmanabdullah9@gmail.com> wrote in message <iujd42$she$1@newscl01ah.mathworks.com>... > dear friends, > > i have t vector; t=linspace(0,.00007,76); > > k vector is [0 0 0 1......1 0 0 ..], its like all zeros except two 1`s, on a different time instants. when i apply this command ; > > k=interp1(tau,k,t); > > tau is also the same as t. one question is that,do we need to interpolate the vector k from one time vector to another of the same length? as here length(t)=length(tau). ================ No. tau and t can be of different lengths. Bear in mind though that if tau=t then the output k will be the same as the input k. So, it doesn't make sense that "tau is also the same as t". > second question is that when i apply this command, the vector k is returned as a single entry???? =============== No, I can't reproduce that, as the following shows >> t=linspace(0,.00007,76); tau= t...

route 0.0.0.0 twice
Hi, I some doubts question regarding a Cisco config. In the config I can see the following two lines: ip route 0.0.0.0 0.0.0.0 192.168.1.1 ip route 0.0.0.0 0.0.0.0 192.168.1.2 I know that these addresses are active in two interfaces. We had a 2Mbit connection that was upgraded to 4 Mbit. Our ISP told us to add the routes and that with those two routes we would be able to use the two links as one. Is this true with Cisco's CEF? My question is: 1. what's the route selected by the packets? Thanks, NC Nuno Cristelo wrote: > Hi, > > I some doubts question regarding a C...

ip 0.0.0.0 is attempting to ....
NIS2004 told me a remote computer at ip 0.0.0.0 is trying to access my computer, and asked if it should allow it. I'm thinking that is probably just the dsl modem and I should allow it. Can anyone confirm or instruct? "Adam Russell" <REMOVE_THIS_adamrussell@sbcglobal.net> wrote in message news:<bro2a6$5lbqu$1@ID-122512.news.uni-berlin.de>... > NIS2004 told me a remote computer at ip 0.0.0.0 is trying to access my > computer, and asked if it should allow it. I'm thinking that is probably > just the dsl modem and I should allow it. Can anyone confirm or instruct? So is this the wrong newsgroup, or does no one know the answer? On 18-Dec-2003, adamrussell@sbcglobal.net (Adam Russell) wrote: > "Adam Russell" <REMOVE_THIS_adamrussell@sbcglobal.net> wrote in message > news:<bro2a6$5lbqu$1@ID-122512.news.uni-berlin.de>... > > NIS2004 told me a remote computer at ip 0.0.0.0 is trying to access my > > computer, and asked if it should allow it. I'm thinking that is > > probably > > just the dsl modem and I should allow it. Can anyone confirm or > > instruct? > > So is this the wrong newsgroup, or does no one know the answer? I do not know NIS2004, but the rule of thumb that makes the most sense to me is: When in doubt, block it. If things (access) still work then you are good, if it don't work, then you try allowing it. ...

Network 0.0.0.0 needed?
When redistributing a default route learned via EIGRP into BGP it seems the route will not propagate into the BGP table unless you have network 0.0.0.0 configured under BGP. Does anyone know why this is necessary? A safety measure perhaps? Thanks! You can also do this with a "neighbor x.x.x.x default-originate" command under "router bgp" BGP was designed for the Internet, where there is no default-route. Scott "Paul Thompson" <shinobi2@sympatico.ca> wrote in message news:v5o2t2dpq2653k37q2ki830dsae2728n5q@4ax.com... > When redistributing a default route learned via EIGRP into BGP it > seems the route will not propagate into the BGP table unless you have > network 0.0.0.0 configured under BGP. Does anyone know why this is > necessary? A safety measure perhaps? > > Thanks! ...

dhclient leasing 0.0.0.0
hi, OS: FreeBSD 4.9-Release im starting the dhclient at bootup from the rc.conf file. in the process list it shows as: /sbin/dhclient -pf /var/run/dhclient.ed1.pid ed1 the ipaddress leased shows: # ifconfig -a .... faith0: flags=8002<BROADCAST,MULTICAST> mtu 1500 ed1: flags=8843<UP,BROADCAST,RUNNING,SIMPLEX,MULTICAST> mtu 1500 inet 0.0.0.0 netmask 0xff000000 broadcast 255.255.255.255 ether 00:02:dd:1f:10:89 after killing the dhclient process and starting it again with: # dhclient everything is fine and i get a working ipaddress. my dhcp config parameters in rc.conf are standard (sysinstall generated). Since my rc.firewall script automatically finds the ipaddress i will have to restart the firewall as well. Does someone have a clue how to persuade dhclient to find the right ip-address at bootup? Also there is no logentry leading to any problems with dhclient. Thanks in advance, sake. sake@snafu.de (sake) writes: > im starting the dhclient at bootup from the rc.conf file. > in the process list it shows as: > /sbin/dhclient -pf /var/run/dhclient.ed1.pid ed1 > the ipaddress leased shows: > # ifconfig -a > ... > faith0: flags=8002<BROADCAST,MULTICAST> mtu 1500 > ed1: flags=8843<UP,BROADCAST,RUNNING,SIMPLEX,MULTICAST> mtu 1500 > inet 0.0.0.0 netmask 0xff000000 broadcast 255.255.255.255 > ether 00:02:dd:1f:10:89 > > after killing the dh...

what is telnet 0.0.0.0 supposed to do?
Hi all. on windows it seems to be an illegal address, on solaris/linux it gives you a login on the localhost. could someone point to some more info on 0.0.0.0 ? yes, I already googled. On Jul 30, 7:08=A0am, adirtymindisajoyforever <getridofthes...@yahoo.com> wrote: > Hi all. > > on windows it seems to be an illegal address, on solaris/linux it > gives you > a login on the localhost. > > could someone point to some more info on 0.0.0.0 ? In principle, if you mean 0.0.0.0 as a destination address, it could just as well be illegal. I don't t...

array 0 0 0...
#include "callFirst.hpp" //contain iostream, namespace, and basic operations int main() { int x[10]; int Ops; for(int i = 0; i < 10; i++){ x[i] = i * 2; } int k = 0; while( k < 10){ int j = 0; cout << x[j]; cout << " "; j++; k++; } int dummy; cin >> dummy; return 0; } why I get output as 0 0 0 0 0 0 0 ... suppose it should be 0 2 4 6 ... how do I fix this? m2k_stp@hotmail.com 写道: > #include "callFirst.h...

memcpy(0,0,0)
Hi, all. This question came up in a code review: are null pointers legal as arguments to memcpy? That is, is the program at the end of this article strictly conforming? (Of course, I check the FAQ first and could not find an answer on point.) I don't have C89 or C99 handy, so I checked draft N869 from here: http://www.open-std.org/jtc1/sc22/wg14/www/docs/n869/n869.txt.gz I note the following: 7.21.1 String function conventions Where an argument declared as "size_t n" specifies the length of the array for a function, "n" can have the value z...

Behavior of 0 and 0.0...
I was playing around with the basic math functions, and I had some questions about the way Ruby handles operations with 0 and 0.0. first we have: $ ruby -v ruby 1.8.6 (2007-09-24 patchlevel 111) [i486-linux] $ irb irb(main):001:0> 0/0 ZeroDivisionError: divided by 0 from (irb):1:in `/' from (irb):1 This is OK, it lets us know that we made a mistake somewhere, but when we try 0.0/0.0 we get: irb(main):002:0> 0.0/0.0 => NaN Mathematically, this is preferable to division error, but, maybe not from a programming standpoint? The question here is why should these tw...

0 + not 0
>>> 0 + not 0 File "<stdin>", line 1 0 + not 0 ^ SyntaxError: invalid syntax >>> What is syntactically wrong with 0 + not 0? On Sat, Jul 11, 2015 at 8:26 PM, candide <c.candide@laposte.net> wrote: >>>> 0 + not 0 > File "<stdin>", line 1 > 0 + not 0 > ^ > SyntaxError: invalid syntax >>>> > > > What is syntactically wrong with 0 + not 0? I'm actually not sure why this can't be handled. Possibly it's a limitation of the parser. C...

0^0 ?
What does 0^0 equal? ALG48, and 49g on approx mode says one. Ti-89 gives one, but with the message, " warning 0^0 replaced by 1". HP49 on exact gives ?. You've stumbled upon one of Math's many mysteries ;-) http://mathforum.org/dr.math/faq/faq.0.to.0.power.html "chris heaton" <cmhthethird@yahoo.com> wrote in message news:89d0a867.0310011839.18b9f546@posting.google.com... > What does 0^0 equal? ALG48, and 49g on approx mode says one. Ti-89 > gives one, but with the message, " warning 0^0 replaced by 1". HP49 on > exact gives ?. c...

0**0
Hello, I didn't find in the standard, what should be the interpretation of 0**0, 0d0**0, etc. ? I ask because I just noticed with Absoft compiler (ver. 11.5.2), that 0d0**0 == 1d0, whereas 0q0**0 == 0q0 (q for quad precision numbers). Thus, porting some double precision code to quad precision gave me unexpected results. Jean-Claude Arbaut In article <506ff947$0$18052$ba4acef3@reader.news.orange.fr>, Jean-Claude Arbaut <jeanclaudearbaut@orange.fr> writes: > I didn't find in the standard, what should be the interpretation > of 0**0, 0d0**0, etc. ? > > I ask because I just noticed with Absoft compiler (ver. 11.5.2), that > 0d0**0 == 1d0, whereas 0q0**0 == 0q0 (q for quad precision numbers). > Thus, porting some double precision code to quad precision gave me > unexpected results. My guess is that you shouldn't be relying on this at all. Both answers are probably "correct" in the sense that the compiler can do anything if the code is invalid, and these operations are probably not allowed, so the question of the "correct" value is moot. Hi, > > I didn't find in the standard, what should be the interpretation > > of 0**0, 0d0**0, etc. ? > > > > I ask because I just noticed with Absoft compiler (ver. 11.5.2), that > > 0d0**0 == 1d0, whereas 0q0**0 == 0q0 (q for quad precision numbers). > > Thus, porting some double precision code ...

static ip but get 0.0.0.0
We have win 2k machine. We set an static ip of 15.15.15.1 then we power off the machine and PC is connected to a HUB. When HUB is powered off when the PC booting up, after win 2k starts we power on the HUB but ipconfig gives we have 0.0.0.0 as an ip address. We use AMD PCNET and we have a dial up network connection configured also. ...

trap source address 0.0.0.0
Hi all i'm using Debian with net-snmp 5.1. If i receive a trap from this host 147.87.19.197 it sends the trap with source address 0.0.0.0 instead of 147.87.19.197. Does somebody know why it is like that? And if i can configure it somewhere. I'm also using net-snmp on RedHat PC's, there it is the version of the rpm package, 5.0.6. It works fine on these PC's, that means they're sending their IP as source address. Thanks for helping Angela HI, I would say that this is correct behavior! You need to get the agent address from the source address when receiving the UDP message. On Tue, 18 Nov 2003, Angela Stempfel wrote: > Hi all > > i'm using Debian with net-snmp 5.1. If i receive a trap from this host > 147.87.19.197 it sends the trap with source address 0.0.0.0 instead of > 147.87.19.197. Does somebody know why it is like that? And if i can > configure it somewhere. > I'm also using net-snmp on RedHat PC's, there it is the version of > the rpm package, 5.0.6. It works fine on these PC's, that means > they're sending their IP as source address. > > Thanks for helping > Angela Regards, /david t. perkins Hallo David just a funny answer: Angela wrote, that the agent doesn't send its IP-Address as source address and you answer: "You need to get the agent address from the source address" (just the thing she wanted to do ;-)) Probabely you talk ...

Why is server starting on 0.0.0.0:3000?
Hi, I just installed the most recent version of ruby and rails on my Fedora Core 5 Linux system. For some reason, my server isn't starting, but I noticed one line upon startup: => Rails application starting on http://0.0.0.0:3000 Shouldn't rails be booting on 127.0.0.1 or localhost or whatever? I didn't read anything about adjusting this setting on the rails download page, but you guys are the experts, so please tell me if this setting needs to change and how to do it. Best, - Dave On Oct 31, 3:32 pm, "laredotorn...@zipmail.com" <laredotorn...@zipmail.com> wrote: > Hi, > > I just installed the most recent version of ruby and rails on my > Fedora Core 5 Linux system. For some reason, my server isn't > starting, but I noticed one line upon startup: > > => Rails application starting onhttp://0.0.0.0:3000 > > Shouldn't rails be booting on 127.0.0.1 or localhost or whatever? I > didn't read anything about adjusting this setting on the rails > download page, but you guys are the experts, so please tell me if this > setting needs to change and how to do it. > > Best, - Dave Many apologies. I meant to post this to comp.lang.ruby. Please disregard. - ...

arp who-has hostname tell 0.0.0.0
Snort was reporting some wierd packets from host 0.0.0.0, so I ran "tcpdump -X src 0.0.0.0" to see what I could see. I saw a steady flow of 0.0.0.0.bootpc packets, but figured they weren't of interest. Then there came a cluster of five arp packets that made no sense to me. 08:46:42.453056 arp who-has HOSTNAME.DOMAINNAME tell 0.0.0.0 0000: 0001 0800 0604 0001 000d 93c3 1b68 0000 ...........=EF=BF=BF.h.. 0010: 0000 0000 0000 0000 0a19 3682 5555 5555 ..........6.UUUU 0020: 5555 5555 5555 5555 5555 5555 5555 UUUUUUUUUUUUUU Any idea what these are all about? Is there a option to have tcpdump report mac-addresses? I don't see it in the man pages. Linolil In article <1122484245.081566.170110@o13g2000cwo.googlegroups.com>, linolil <linolil@equoria.net> wrote: :Snort was reporting some wierd packets from host 0.0.0.0, :so I ran "tcpdump -X src 0.0.0.0" to see what I could see. :I saw a steady flow of 0.0.0.0.bootpc packets, but figured :they weren't of interest. They probably were the key to the matter. :Then there came a cluster of :five arp packets that made no sense to me. :08:46:42.453056 arp who-has HOSTNAME.DOMAINNAME tell 0.0.0.0 The packet is using IP addresses internally, and tcpdump is doing a DNS reverse lookup to turn that IP into HOSTNAME.DOMAINNAME . I suspect that what you are seeing is a DHCP request (source IP must be 0.0.0.0 for those), followed by a DHC...

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