Hi ,

I am facing this problem .
SunOS INHYLB1-SUN4 5.9 Generic_112233-10 sun4u sparc
SUNW,Sun-Fire-V440

After I link an executable , I cannot run it:

ld.so.1: ./ns.run: fatal: libgcc_s.so.1: open failed: No such file or
directory
The binary ns.run is build in gcc version 3.3.2. But in the test
solaris box there is no gcc installed , also there is no
libgcc_s.so.1.

I do not want to add the libgcc_s.so.1 directory to LD_LIBRARY_PATH
(this is not an automated solution), I would prefer that the this path
is somehow saved into the executable.

how can I do it?

Thanks,
Abhijit

Have a look at 'man ld' or the "Linkers and loaders" guide at sun site.

There is an option in ld to bind library path in binary file. I don't
remember the exact command right now.
Cheers,
Manu
------------------
Manu Garg
http://manugarg.freezope.org

I could not find anything . Can you please let me know the exact option
>
Thanks,
Abhijit

"Abhijit"  wrote:

> I could not find anything . Can you please let me know the exact option

-R/the/right/path
If you are linking with gcc and not calling ld yourself, you may have to
protect it with "-Wl,", depending on how good your gcc specs are.

On Wed, 22 Dec 2004 00:37:51 -0800, Abhijit wrote:

> I could not find anything . Can you please let me know the exact option

In your Makefile

LDFLAGS=-L/path_to_libgcc -R/path_to_libgcc ....

Dave Uhring wrote:
> On Wed, 22 Dec 2004 00:37:51 -0800, Abhijit wrote:
> 
> 
>>I could not find anything . Can you please let me know the exact option
> 
> 
> In your Makefile
> 
> LDFLAGS=-L/path_to_libgcc -R/path_to_libgcc ....
> 

Or simply use -static-libgcc.

-- 
Henry Townsend