f



delta time = time stop - time start

I'm using Python to parse a bunch of s/w test files and make csv files for later report generation by MS ACCESS....(my boss
loves the quick turn-around compared to C). Each log file may contain one or more 'sessions', and each session may contain
one or more 'nodes'.

Each session in the log has an ASCII  start and stop time, as does each node.
I have the basic parse part done for parameters, errors, etc., but noticed my routine for determining how long each
session/node took (delta time) was a bit repetitive, so decided to make a 'stand-alone' routine to handle this.

The time format from the log is in the format of:
hh:mm:ss
and is a string with leading zeros where appropiate. Date is never a factor. The longest "delta" is maybe 5 hours.

The routine I came up with is below, but seems a bit clunky.
Is there a better way of doing this? I think it relies too much on integers rounding off in the proper direction, a la
d_time_hr = d_time / 3600 below.

Also, this will have to transition to Linux, if that makes a difference.

START CODE:

import string

def deltatime(start, stop):

    t_start = (string.atoi(start[0:2]) * 3600) + (string.atoi(start[3:5]) * 60) + string.atoi(start[6:8])
    t_stop  = (string.atoi(stop [0:2]) * 3600) + (string.atoi(stop [3:5]) * 60) + string.atoi(stop [6:8])

    if t_start < t_stop:
        d_time = t_stop - t_start
    else:
        d_time = (86400 - t_start) + t_stop

    d_time_hr  =  d_time / 3600
    d_time_min = (d_time - d_time_hr * 3600) / 60
    d_time_sec = (d_time - d_time_hr * 3600) - (d_time_min * 60)

    return str(d_time_hr) + 'hr ' + str(d_time_min) + 'min ' + str(d_time_sec) + 'sec'

END CODE

TRY IT

print deltatime('23:45:00', '02:55:03')

RETURNS

3hr 10min 3sec

Thanks.....Norm
PS Please reply via email (engsolnorm@hotmail.com) until my ISP gets fixed.


0
1/26/2004 6:08:05 AM
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On Mon, 2004-01-26 at 04:08, engsol wrote:
[...]
> The routine I came up with is below, but seems a bit clunky.
> Is there a better way of doing this? I think it relies too much on integers rounding off in the proper direction, a la
> d_time_hr = d_time / 3600 below.
> 

You can use mx.DateTime
(http://www.lemburg.com/files/python/mxDateTime.html).
Then, the code will look like this:

from mx import DateTime
start = DateTime.now()
# do something ...
stop = DateTime.now()
delta = (stop - start).strftime("%H:%M:%S")

hope it helps.

> Also, this will have to transition to Linux, if that makes a difference.
> 
> START CODE:
> 
> import string
> 
> def deltatime(start, stop):
> 
>     t_start = (string.atoi(start[0:2]) * 3600) + (string.atoi(start[3:5]) * 60) + string.atoi(start[6:8])
>     t_stop  = (string.atoi(stop [0:2]) * 3600) + (string.atoi(stop [3:5]) * 60) + string.atoi(stop [6:8])
> 
>     if t_start < t_stop:
>         d_time = t_stop - t_start
>     else:
>         d_time = (86400 - t_start) + t_stop
> 
>     d_time_hr  =  d_time / 3600
>     d_time_min = (d_time - d_time_hr * 3600) / 60
>     d_time_sec = (d_time - d_time_hr * 3600) - (d_time_min * 60)
> 
>     return str(d_time_hr) + 'hr ' + str(d_time_min) + 'min ' + str(d_time_sec) + 'sec'
> 
> END CODE

[]'s
Salgado
-- 
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weapons of mass destruction were used in its construction. 
Read his report here:
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0
salgado (3)
1/26/2004 11:07:34 AM
engsol <engsolnorm@ipns.com> wrote in message news:<cs9910pcgktdrp1e8abctoptue7braqvqu@4ax.com>...
> I'm using Python to parse a bunch of s/w test files and make csv files for later report generation by MS ACCESS....(my boss
> loves the quick turn-around compared to C). Each log file may contain one or more 'sessions', and each session may contain
> one or more 'nodes'.
> 
> Each session in the log has an ASCII  start and stop time, as does each node.
> I have the basic parse part done for parameters, errors, etc., but noticed my routine for determining how long each
> session/node took (delta time) was a bit repetitive, so decided to make a 'stand-alone' routine to handle this.
> 
> The time format from the log is in the format of:
> hh:mm:ss
> and is a string with leading zeros where appropiate. Date is never a factor. The longest "delta" is maybe 5 hours.
> 
> The routine I came up with is below, but seems a bit clunky.
> Is there a better way of doing this? I think it relies too much on integers rounding off in the proper direction, a la
> d_time_hr = d_time / 3600 below.

It also relies on -Qold.  Please use the // operator for integer
division.  Or you're going to regret it when you upgrade to Python
3.0.

> Also, this will have to transition to Linux, if that makes a difference.

In your code, it makes no difference.  I'm using a Linux box right
now.

> START CODE:
> 
> import string

Unless you have a very old version of Python, this is no longer
needed; string.atoi has been officially replaced with the "int"
constructor.

> def deltatime(start, stop):
> 
>     t_start = (string.atoi(start[0:2]) * 3600) + (string.atoi(start[3:5]) * 60) + string.atoi(start[6:8])
>     t_stop  = (string.atoi(stop [0:2]) * 3600) + (string.atoi(stop [3:5]) * 60) + string.atoi(stop [6:8])

Rather than count character positions, take advantage of the fact that
the strings are colon-delimited.

      def toSeconds(timeString):
         hour, min, sec = map(int, timeString.split(':'))
         return (hour * 60 + min) * 60 + sec

      t_start = toSeconds(start)
      t_stop  = toSeconds(stop)
      
>     if t_start < t_stop:
>         d_time = t_stop - t_start
>     else:
>         d_time = (86400 - t_start) + t_stop

You can eliminate the if-else test by taking advantage of Python's %
operator

      d_time = (t_stop - t_start) % 86400

>     d_time_hr  =  d_time / 3600
>     d_time_min = (d_time - d_time_hr * 3600) / 60
>     d_time_sec = (d_time - d_time_hr * 3600) - (d_time_min * 60)

Rather than calculate remainders the hard way, use the % operator.  Or
since you need both the quotient and remainder, use the divmod
function.

      d_time_min, d_time_sec = divmod(d_time, 60)
      d_time_hr, d_time_min = divmod(d_time_min, 60)

>     return str(d_time_hr) + 'hr ' + str(d_time_min) + 'min ' + str(d_time_sec) + 'sec'

A more concise way of writing this is

      return '%dhr %dmin %ssec' % (d_time_hr, d_time_min, d_time_sec)

The complete rewritten function is

def deltatime(start, stop):
   def toSeconds(timeString):
      hour, min, sec = map(int, timeString.split(':'))
      return (hour * 60 + min) * 60 + sec
   t_start = toSeconds(start)
   t_stop  = toSeconds(stop)
   d_time = (t_stop - t_start) % 86400
   d_time_min, d_time_sec = divmod(d_time, 60)
   d_time_hr, d_time_min = divmod(d_time_min, 60)
   return '%dhr %dmin %ssec' % (d_time_hr, d_time_min, d_time_sec)

which is still too verbose for my tastes; I would rewrite it as:

def deltatime(start, stop):
   def toSeconds(timeString):
      hour, min, sec = map(int, timeString.split(':'))
      return (hour * 60 + min) * 60 + sec
   d_time_min, d_time_sec = divmod(toSeconds(stop) - toSeconds(start),
60)
   d_time_hr, d_time_min = divmod(d_time_min, 60)
   return '%dhr %dmin %ssec' % (d_time_hr % 24, d_time_min,
d_time_sec)
0
danb_83 (421)
1/26/2004 12:06:26 PM
Reply: